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3 years ago

The exterior angles of a triangle are (2x+10), (3x+5), and (2x+40) 0.

Mathematics

1 answer:

Roman55 [17]3 years ago

7 0

Step-by-step explanation:

i. (2x+10)+(3x+5)+(2x+40) = 360

2x+3x+2x+10+5+40= 360

7x+55 =360

7x=360-55

7x= 305

7. 7

x= 43.57=43.6

ii. 2x+10= 180

2x=180-10

2x= 170

2. 2

x=85

3x+5 =180

3x=180-5

3x=175

3. 3

x= 57.5

2x+40=180

2x=180-40

2x=140

2. 2

x= 70

From the above 3x+5 which is 57.5 is the smallest interior angle of the triangle

iii. The largest interior angle of the triangle is 2x+10 which is 85

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3 years ago

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GaryK [48]

In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.

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Cross multiply both sides of the equation.

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Subtract 6x on both sides of the equation.

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Divide both sides of the equation by -5.

$-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}$ $y=\frac{4}{5}x-\frac{2}{5}$

Therefore, the slope of the first equation is 4/5.

Let's now simplify the second equation.

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Add x on both sides of the equation.

$-4y-x+x=4x+5+x$ $-4y=5x+5$

Divide both sides of the equation by -4.

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Therefore, the slope of the second equation is -5/4.

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1 year ago

62,400 is what percentage of 156,000

STatiana [176]

62400 is what percent of 156000
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4 years ago

Read 2 more answers