Help a brother out, I'm lost

1 answer:

9966 [12]3 years ago

8 0

Answer:

I think that the answer is 25,180.

Step-by-step explanation:

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irga5000 [103]

I'm pretty sure when you graph the lines, both of them meet at 5.

8 0

4 years ago

vivado [14]

A = ( 15 , 15 )

B = ( 6 , 33 )

$slope = \frac{y(b) - y(a)}{x(b) - x(a)} \\$

$slope = \frac{33 - 15}{ 6 - 15} \\$

$slope = \frac{18}{ - 9} \\$

$slope = - 2$

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

7 0

3 years ago

GREYUIT [131]

Answer:

$\displaystyle y' = \frac{-2}{x \ln (10)[\log (x) - 2]^2}$

General Formulas and Concepts:

Calculus

Differentiation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Derivative Rule [Basic Power Rule]:

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle y = \frac{\log (x)}{\log (x) - 2}$

Step 2: Differentiate

[Function] Derivative Rule [Quotient Rule]: $\displaystyle y' = \frac{[\log (x) - 2][\log (x)]' - [\log (x) - 2]'[\log (x)]}{[\log (x) - 2]^2}$
Rewrite [Derivative Rule - Addition/Subtraction]: $\displaystyle y' = \frac{[\log (x) - 2][\log (x)]' - [\log (x)' - 2'][\log (x)]}{[\log (x) - 2]^2}$
Logarithmic Differentiation: $\displaystyle y' = \frac{[\log (x) - 2]\frac{1}{\ln (10)x} - [\frac{1}{\ln (10)x} - 2'][\log (x)]}{[\log (x) - 2]^2}$
Derivative Rule [Basic Power Rule]: $\displaystyle y' = \frac{[\log (x) - 2]\frac{1}{\ln (10)x} - \frac{1}{\ln (10)x}[\log (x)]}{[\log (x) - 2]^2}$
Simplify: $\displaystyle y' = \frac{\frac{\log (x) - 2}{\ln (10)x} - \frac{\log (x)}{\ln (10)x}}{[\log (x) - 2]^2}$
Simplify: $\displaystyle y' = \frac{\frac{-2}{\ln (10)x}}{[\log (x) - 2]^2}$
Rewrite: $\displaystyle y' = \frac{-2}{x \ln (10)[\log (x) - 2]^2}$