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3241004551 [841]
4 years ago
9

Ten less than two times a number

Mathematics
1 answer:
qwelly [4]4 years ago
8 0

Answer:

10

Step-by-step explanation:

If x is the number.

Then twice the number is 2x

Then 10 less than (twice the number) is 2x−10

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What is the solution set of this system of equations?
Maksim231197 [3]

Answer:

No real solutions.

Step-by-step explanation:

y=x^2-3x-4

x=y+8

I'm going to subtract the second expression for y and plug it into the first equation.

So solving x=y+8 for y by subtracting 8 on both sides gives us y=x-8.

I'm going to insert this for the first y like so:

x-8=x^2-3x-4

Now I'm going to move everything to one side.

I'm going to subtract x on both sides and add 8 on both sides.

0=x^2-3x-x-4+8

Simplifying:

0=x^2-3x+4

Now our job since the coefficient of x^2 is 1 is to find two numbers that multiply to be 4 and at the same time add up to be -3. I can't think of any such numbers.

Let's check the discriminant.

Compare x^2-3x+4 to ax^2+bx+c.

So a=1,b=-3,c=4.

The discriminant is b^2-4ac.

So plugging in our numbers we get (-3)^2-4(1)(4).

Time to simplify:

(-3)^2-4(1)(4)

9-16

-7

So since the discriminant is negative, then the solutions will not be real.

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3 years ago
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This would be y=-x-6. The slope is the number before x and the y intercept is the number coming after. This shows that it must be y=-1x-6
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The additive inverse of 5/9 is​
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I think that it’s -5 (:
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I need some math help please
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Answer:

A

Step-by-step explanation:

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