Question

(-3,-3) ; parallel to -x+3y=9

Answer 1

Rewriting the equation in the form y=mx+c
-x+3y=9
3y=x+9
y=$\frac{1}{3} x+3$
Gradient is 1/3
Since parallel lines have similar gradients,
$\frac{y--3}{x--3}= \frac{1}{3}$
y+3=$\frac{1}{3} (x+3)$
y+3=$\frac{1x}{3} +1$
y=$\frac{1x}{3} -2$