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nikitadnepr [17]
2 years ago
12

Please help me write quadratic equation given the roots and the leading coefficient

Mathematics
1 answer:
Pie2 years ago
5 0

Answer:

Example Question: f(x) = 2x^2 + 2x - 1


If the leading coefficient is positive, the graph will be opening up (U) if the leading coefficient is negative, the graph will be opening down (n)


Roots are the x-intercepts that help find the axis of symmetry (add the two roots together and divide the result by 2 to get the axis of symmetry)


To find the vertex, simply imput the axis of symmetry into the given equation.


And that’s about it.

Step-by-step explanation:

I don’t know what you’re asking for??

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Use the substitution method to solve the given system of equations. Write your answer as an ordered pair, (x, y).
Gnoma [55]

Answer:

(-3, -2)

Step-by-step explanation:

Look at the second equation, we can easily rearrange it to make x the subject.

x - 4y = 5

x = 4y + 5

Now lets put that into the second equation

2x - 2y = -2

2(4y + 5) - 2y = -2

6y + 10 = -2

6y = -12

y = -2

Now lets find x!

x = 4y + 5

x = 4(-2) + 5

x = -3

Now lets format the answer like the question says (ordered pair)

(-3, -2)

Recap: We used substitution and made an equation to work out one of the variables first, then found the second variable using the first.

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3 years ago
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The easiest way is to graph it based upon the slope (m) and y-intercept (b), in the standard slope-intercept form: y = m (x) + b.
The line above intercepts the y-axis at y = -2, which is b. The slope (m) = rise/run = (y2-y1)/(x2-x1 ); so for the point (-4, 2) to (-6, 4) is:
(4-2)/(-6--4) = 2/(-6+4) = 2/-2 = -1.
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Now the other form of an equation is point-slope: y-k = m (x-h), where the point is at (h, k)
and if we pick -5 for x (bc 5 it listed in 3 of the answers), the y at x=-5 looks like around +3
so we get: y-k = -1 (x--5)...
y-3 = -(x+5)... therefore D) is the correct answer:
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Step-by-step explanation:

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Step-by-step explanation:

The first is correct.

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