(4x+5)(4x-5) is equal to 16x^2+20x-20x-25
The positive and negative 20x cancel out
Leaving you with: 16x^2 - 25
[S/N this is a pattern that shows up a decent amount. Whenever you have something that looks like (x^2-y^2) it factors out to (x+y)(x-y). It might be helpful to remember]
The next one, (4x+5)2, just follows the distributive property. Multiply both components within the parentheses bye the coefficient of 2: 8x+10
Hello!
I believe it looks like this..
2*x+5=9
Btw, x = 3 is your answer if you're wondering..
Hope this helps! ☺♥
Answer:
12 5/12 cans of white make
Step-by-step explanation:
Solve for x over the real numbers:x = -2. x^2 - 8 x + 6
Hint: | Rewrite the right hand side of the equation.-2. x^2 - 8 x + 6 = -2 x^2 - 8 x + 6:x = -2 x^2 - 8 x + 6
Hint: | Move everything to the left hand side.Subtract -2 x^2 - 8 x + 6 from both sides:2 x^2 + 9 x - 6 = 0
Hint: | Write the quadratic equation in standard form.Divide both sides by 2:x^2 + (9 x)/2 - 3 = 0
Hint: | Solve the quadratic equation by completing the square.Add 3 to both sides:x^2 + (9 x)/2 = 3
Hint: | Take one half of the coefficient of x and square it, then add it to both sides.Add 81/16 to both sides:x^2 + (9 x)/2 + 81/16 = 129/16
Hint: | Factor the left hand side.Write the left hand side as a square:(x + 9/4)^2 = 129/16
Hint: | Eliminate the exponent on the left hand side.Take the square root of both sides:x + 9/4 = sqrt(129)/4 or x + 9/4 = -sqrt(129)/4
Hint: | Look at the first equation: Solve for x.Subtract 9/4 from both sides:x = sqrt(129)/4 - 9/4 or x + 9/4 = -sqrt(129)/4
Hint: | Look at the second equation: Solve for x.Subtract 9/4 from both sides:Answer: x = sqrt(129)/4 - 9/4 or x = -9/4 - sqrt(129)/4
