Let the angle of elevation is x and the height of the rocket from the ground is y
tanx = y/15
by differentiating both sides with respect to T
sec²x·dx/dt = (dy/dt)/15
at y = 30 , the hypotenuse of the triangle = 15√5
sec²x=(15√5/15)²=5
5 dx/dt = 11/15
dx/dt = 11/75 rad/sec
Answer:
1st one is B
Step-by-step explanation:
2nd one is the 1st one
Let d be distance travelled when they are level , and t = time that nora took to get level with mason
for Nora
6 = d/t
d = 6t
for Mason
5 = d / (t + 35)
d = 5 ( t + 350
so 6t = 5(t + 35)
solve for t
Answer:
1. 5.5 ( Cant see numbers that well)
2. 2.1
3. 1.12
4. 0.27
5. 0.84
6. 1.6
Step-by-step explanation:
Line them up with whole numbers and decimals and then subtract right to left.
Answer: No Solution
Step-by-step explanation: The Answer Is No Solution.
Have A Great Day!
