Question

• A gas occupies what volume at a pressure of 5.4atm, 3.5 moles of gas, at 333 K?​

Answer 1

Answer: 17.71L

Explanation:

The volume can be calculated by using the ideal gas equation which is given as:

PV =nRT

Where P = Pressure, V= Volume, n= number of moles, R= gas constant and T = Temperature

From the above question :

P =5.4 ATM, V= ? n = 3.5 , R =0.082057 L atm /mol/K, T= 333K

PV = nRT

Make V subject of the formula we then have:

V= nRT/P

= 3.5 x 0.082507 L x 333 / 5.4

= 95.64 / 5.4 = 17.7L