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Drupady [299]
3 years ago
9

• A gas occupies what volume at a pressure of 5.4atm, 3.5 moles of gas, at 333 K?​

Chemistry
1 answer:
IrinaK [193]3 years ago
5 0

Answer: 17.71L

Explanation:

The volume can be calculated by using the ideal gas equation which is given as:

PV =nRT

Where P = Pressure, V= Volume, n= number of moles, R= gas constant and T = Temperature

From the above question :

P =5.4 ATM, V= ? n = 3.5 , R =0.082057 L atm /mol/K, T= 333K

PV = nRT

Make V subject of the formula we then have:

V= nRT/P

= 3.5 x 0.082507 L x 333 / 5.4

= 95.64 / 5.4 = 17.7L

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Electrical to chemical energy

Explanation:

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A solution is prepared at that is initially in nitrous acid , a weak acid with , and in sodium nitrite . Calculate the pH of the
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Answer:

4.07

Explanation:

There is some info missing. I think this is the original question.

<em>A solution is prepared at 25 °C that is initially 0.057 M in nitrous acid (HNO₂), a weak acid with Ka = 4.5 × 10⁻⁴, and 0.30 M in sodium nitrite (NaNO₂). Calculate the pH of the solution. Round your answer to 2 decimal places.</em>

<em />

Nitrous acid is a weak acid and nitrite (coming from sodium nitrite) is its  conjugate base. Together, the form a buffer system. We can calculate its pH using the Henderson-Hasselbach equation.

pH = pKa + log [base]/[acid]

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When barium chloride reacts with potassium sulfate, barium sulfate and potassium chloride arc produced. The balanced equation fo
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Answer:

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The reaction produces 2 moles of barium sulfate ( ratio is 1:1) and 4 moles of potassium chloride. (Ratio with this is 2:4)

Explanation:

This is the reaction:

BaCl₂(aq) + K₂SO₄(aq) → BaSO₄(s) + 2KCl(aq)

Ratio between the reactants is 1:1, so if 2 moles of potassium sulfate react, The reaction consumes 2 moles of barium chloride

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