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AleksAgata [21]
3 years ago
5

The first term is 1 in the geometric sequence 1,-3,9,-27,...what is the seventh term of the geometric sequence?

Mathematics
1 answer:
dezoksy [38]3 years ago
7 0
729 because all you do is multiply the previous number by -3
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Help me pls AAAAAAAA
erastovalidia [21]

Answer:

10/3 liters

Step-by-step explanation:

Divide (4/3) by 2, then multiply by 5

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I have to factor 14 and 22 to find the greatest common factor​
Monica [59]

Answer: The GCF is 2

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In ΔUVW, w = 9 cm, v = 2.2 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Alja [10]

Complete Question

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answer:

16.5°

Step-by-step explanation:

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

We solve using Sine rule formula

a/sin A = b/sin B

We are solving for angle W

∠V=136°

Hence:

22 /sin 136 = 9 /sin W

Cross Multiply

22 × sin W = sin 136 × 9

sin W = sin 136 × 9/22

W = arc sin [sin 136 × 9/2.2]

W = 16.50975°

W = 16.5°

3 0
3 years ago
Select all the simplified expression <br>​
sineoko [7]

Answer:

1 / 3^5

1/ 243

Step-by-step explanation:

3^4 ÷ 3^9

We know that a^b ÷ a^c = a^ ( b-c)

3 ^ ( 4-9)

3^ -5

We can rewrite this as a^-b = 1/ a^b

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Identify the correct corresponding parts
andrey2020 [161]

Answer:

The correct corresponding part is;

\overline {CB} ≅ \overline {CD}

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment \overline {CA} is congruent to \overline {CE} ( \overline {CA} ≅ \overline {CE})

Segment \overline {CB} is congruent to \overline {CD} ( \overline {CB} ≅ \overline {CD})

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment \overline {AB} is congruent to \overline {DE} (\overline {AB} ≅ \overline {DE}) by CPCTC

Segment \overline {AE} bisects \overline {BD}

Segment \overline {BD} bisects \overline {AE}

Therefore, the correct option is \overline {CB} ≅ \overline {CD}

3 0
3 years ago
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