4 years ago

Evaluate the expression.

Mathematics

1 answer:

Karo-lina-s [1.5K]4 years ago

6 0

Answer:

5. 27

6. -12

7. -15

Step-by-step explanation:

add and subtract

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Find the inflection point of the function of f(x) = x³ -6x² +12x

Wewaii [24]

Points of inflections are zeroes of the second derivative. We have:

$f(x)=x^3-6x^2+12x\implies f'(x)=3x^2-12x\implies f''(x)=6x-12$

So, the second derivative equals zero if and only if

$f''(x)=0\iff 6x-12=0 \iff 6x=12 \iff x=2$

So, this is the only point of inflection of this function.

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3 years ago

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Ugo [173]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

You synthetic division to find P(3) for p(x)=x^4-6x^3-4x^2-6x-2

klio [65]

By the polynomial remainder theorem, the remainder upon dividing $p(x)$ by $x-3$ will be the value of $p(3)$ .

... | 1 ... -6 ... -4 ... -6 .... -2
3. | .. ... 3 ... -9 ... -39 .. -135
--------------------------------------
... | 1 ... -3 ... -13 . -45 .. -137

So you have

$\dfrac{x^4-6x^3-4x^2-6x-2}{x-3}=x^3-3x^2-13x-45-\dfrac{137}{x-3}$

which means $p(3)=-137$ .

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anastassius [24]

P(head)=178/200
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