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3 years ago

12

Sandy wants to make a punch recipe with 2 parts pineapple juice to 6 parts ginger ale if you wants to increase the recipe using

a parts pineapple juice,
How much ginger-ale should she use?
18
28
(24

1 answer:

Blizzard [7]3 years ago

4 0

Answer:

24

Step-by-step explanation:

If you go from 2 parts pineapple to 8, thats a 4x increase. Therefore 6x4=24 (6 from the Ginger)

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G(x)=3x+2(x+1) evaluate g(7)

lianna [129]

G(x) = 3x + 2(x + 1)

g(7) = 3(7) + 2(7 + 1)

g(7) = 21 + 2(8)

g(7) = 21 + 16

g(7) = 37

5 0

2 years ago

small cubes with edge lengths of 1/4 inch will be packed into the right rectangular prism shown.( the base is 4 1/2, the width i

ss7ja [257]

General Idea:

We need to find the volume of the small cube given the side length of the small cube as 1/4 inch.

Also we need to find the volume of the right rectangular prism with the given dimension (the height is 4 1/2, the width is 5, and the length is 3 3/4).

To find the number of small cubes that are needed to completely fill the right rectangular prism, we need to divide volume of right rectangular prism by volume of each small cube.

Formula Used:

$Volume \; of \; Cube = a^3 \; \\\{where \; a \; is \; side \; length \; of \; cube\}\\\\Volume \; of \; Right \; Rectangular \; Prism=L \times W \times H\\\{Where \; L \; is \; Length, \; W \; is \; Width, \;and \; H \; is \; Height\}$

Applying the concept:

Volume of Small Cube:

$V_{cube}= (\frac{1}{4} )^3= \frac{1}{64} \; in^3\\\\V_{Prism}= 3 \frac{3}{4} \times 5 \times 4 \frac{1}{2} = \frac{15}{4} \times \frac{5}{1} \times \frac{9}{2} = \frac{675}{8} \\\\Number \; of \; small \; cubes= \frac{V_{Prism}}{V_{Cube}} = \frac{675}{8} \div \frac{1}{64} \\\\Flip \; the \; second \; fraction\; and \; multiply \; with \; the \; first \; fraction\\\\Number \; of \; small \; cubes \;= \frac{675}{8} \times \frac{64}{1} = 5400$

Conclusion:

The number of small cubes with side length as 1/4 inches that are needed to completely fill the right rectangular prism whose height is 4 1/2 inches, width is 5 inches, and length is 3 3/4 inches is <em><u>5400 </u></em>

4 0

3 years ago

Read 2 more answers

A model of a rectangular patio at a landscaping business will be enlarged by a scale factor of 2 when it is installed in a custo

VARVARA [1.3K]

Answer:

C) The area of the landscape model is A = 40 sq ft.

Step-by-step explanation:

The original dimensions of the rectangular patio model is

Length = L

Width = W

Area of the patio model = LENGTH x WIDTH = L x W

⇒ A = L W ............. (1)

Now, the new area A" is enlarged by a factor of 2

⇒ The new Length = L" = (2 L)

The new Width = W" = (2 W)

So, AREA" = L" x W" = (2 L) x (2 W) = 4 (L W)

⇒ A " = 4 (L W)

But, L W = A .. from (1)

⇒ A" = 4 A

But, the area of the new enlarged patio is 160 square feet.

⇒ 160 sq ft = 4 x A

or, A = 160 / 4 =40 sq ft

⇒ A = 40 sq ft.

Hence, the area of the landscape model is A = 40 sq ft.

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3 years ago

Read 2 more answers

a triangle has verticals A(-5,-4), B(2,6), C(4,-3) The center of dilation is the origin and (x,y) (3x,3y). what are the vertices

Gnom [1K]

A' (3(-5),3(-4))= (-15,-12)

B' (3(2),3(6))=(6,18)

C'(3(4),3(-3))=(12,-9)

6 0

1 year ago

Physics students were modeling the height of a ball once it was dropped from the top of a 10 foot ladder. The

julsineya [31]

Answer:

<em>Interval notation: [0, 2.236]</em>

<em>Set Builder notation: </em> $\{t\ |\ 0\le t\le 2.236\}$

Step-by-step explanation:

Given that:

Equation of height of the ball dropped from a height of 10 foot, as:

$h(t) = 10 - 2t^2$

Where $t$ is the time since the ball was dropped.

To find:

The domain of the function in Interval and set builder notation.

Solution:

<em>Domain of a function </em>is defined as the set of valid input values that can be given to the function for which the function is defined.

Here, input is time.

We can not have negative values for time.

Therefore, starting value for time will be <em>0 seconds</em>.

And the value of height can not be lesser than that of 0 ft.

$0= 10 - 2t^2\\\Rightarrow 2t^2=10\\\Rightarrow t^2=5\\\Rightarrow t =2.236\ seconds$

Maximum value for time can be 2.236 seconds.

Therefore the domain is:

<em>Interval notation: [0, 2.236]</em>

<em>Set Builder notation: </em> $\{t\ |\ 0\le t\le 2.236\}$

4 0

3 years ago