All categories

3 years ago

Find the area of a circle whose radius is 12 in. Round to the nearest tenth

Mathematics

2 answers:

irina1246 [14]3 years ago

6 0

Area of a circle = pi r^2 = pi * 12^2 = 452.4 in^2 to nearest tenth.

AysviL [449]3 years ago

4 0

Answer:

Area = pi r²

Area = 22/7 × 12 × 12 = 452.57 in²

You might be interested in

Given g(x)=-5x-4, solve for x when g (x)=1

zubka84 [21]

Answer:

1 = -5x-4 add 4 to both sides

-5x = 1+4 divide both sides by (-5)

x = -5/5

x= -1

5 0

3 years ago

Which mixes number is equivalent to the improper fraction 17/10

zalisa [80]

Answer:

1 7/10

Step-by-step explanation:

Your Welcome :)

4 0

3 years ago

Read 2 more answers

Would you rather discover alien life or an animal that was thought to be extinct?

Vikentia [17]

$\boxed{I\; would\; say\; an\; animal\; that\; was\; thought\; to\; be\; extinct.}$

≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈

The reason i say this is because i don't really want to run into something that i don't know much about. I do know quite a bit about extinct animals more than i do aliens. So, that's my reasoning.

≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈

$\boxed{Hope\;i\;helped!}\\\\\boxed{Thanks,\;AnimeBrainly}$

3 0

3 years ago

trey went to the batting cages to practice hitting. he rented a helmet for $4 and paid $0.75 for each group of 20 pitches. if he

Digiron [165]

First subtract 4 from 7 since they are just asking for the amount he paid for pitches. Then, take the difference (3) and divide it by .75 to get your answer (4 groups).

5 0

3 years ago

A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43

Umnica [9.8K]

Answer:

a) $z = 1.645$

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$ . This is the critical value, the answer for a).

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015$

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0

3 years ago