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3 years ago

12

What value of x is in the solution set of –2(3x + 2) > –8x + 6?

2 answers:

Readme [11.4K]3 years ago

5 0

Answer:

The Answer is D: 6 on edge

Step-by-step explanation:

Yakvenalex [24]3 years ago

4 0

In solving inequalities, it is best to be observant of the signs. As these negative or positive signs will determine whether or not we will have to switch the inequality signs.

–2(3x + 2) > –8x + 6
-6x -4 > -8x +6
Transfer and combine like terms.
-6x + 8x > 6 + 4
2x > 10
x > 5

The final answer is 5. Using this solution, we didn't have to switch the inequality sign because we avoided the negative signs. hope this helps you have an amazing day/night

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Complete the point-slope equation of the line through (2,3)(2,3)left parenthesis, 2, comma, 3, right parenthesis and (7,4)(7,4)l

vovikov84 [41]

Answer:

$y = \frac{1}{5}x +\frac{13}{5}$

Step-by-step explanation:

Given

$(x_1,y_1) = (2,3)$

$(x_2,y_2) = (7,4)$

Required

Complete the equation y - 4.....

First, we need to determine the slope as follows:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{4 - 3}{7 - 2}$

$m = \frac{1}{5}$

The equation is then calculated as thus:

$y - y_1 = m(x - x_1)$

This gives:

$y - 4 = \frac{1}{5}(x -7)$

Open bracket

$y - 4 = \frac{1}{5}x -\frac{7}{5}$

Add 4 to both sides

$y - 4 +4= \frac{1}{5}x -\frac{7}{5} + 4$

$y = \frac{1}{5}x -\frac{7}{5} + 4$

$y = \frac{1}{5}x +\frac{-7+20}{5}$

$y = \frac{1}{5}x +\frac{13}{5}$

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