Answer:
a line labeled g of x that passes through points negative 1, negative 2 and 0, 2
Step-by-step explanation:
we have


To determine g(x), substitute the variable x by (x+1) in the function f(x)
so





therefore
a line labeled g of x that passes through points negative 1, negative 2 and 0, 2
16)
s^1/4 * s^1/4 * s^1/4 * s^1/4 = s^(1/4 + 1/4+1/4+1/4) = s^4/4 = s
Answer is s
15) Answer is 1. (because any number to the 0 exponent is equal 1 , except 0)
17)
= (t^3/6)^2 = t^6/6 = t
Answer is t