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2 years ago

8

The perimeter of a square is 44 cm find the area

2 answers:

krok68 [10]2 years ago

7 0

121cm

Perimeter = sum of all sides

A square has 4 equal sides, therefore 44/4 = 11, so the length of each side in the square is 11cm.

Area of square = length x width

Area = 11 x 11

Area = 121cm

Alexus [3.1K]2 years ago

6 0

Answer:

The given perimeter is \[44cm\]. Hence, the area of the given square is \[121c{m^2}\].

Step-by-step explanation:

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vfiekz [6]

Answer:

33 cm per year

Step-by-step explanation:

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Consider the given function:

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3 years ago

Mrs. Terrace cut a small birthday cake into 6 equal pieces for 6 children. One child was not hungry, so she gave the birthday bo

ELEN [110]

Missing part of question:

Draw a tape diagram to show how much cake each of the five children received.

Answer:

See attachment

Step-by-step explanation:

Given

$Equal\ Pieces = 6$

$Children = 5$

Required

Tape diagram to represent the scenario

Because one child is not hungry, the number of children to share the cake becomes 6.

So, first we calculate the share of each child.

$Share = \frac{Pieces}{Children}$

$Share = \frac{6}{5}$

$Share = 1.2$

See attachment for tape diagram

The tape diagram implies that:

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or

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or

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3 years ago

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masya89 [10]

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8 0

3 years ago

If Smith is guilty, then Jones is innocent. If Jones is innocent, then Smith is guilty. Write each biconditional statement in ex

Volgvan

Answer:

The required biconditional statement is: If Smith is guilty, if and only if Jones is innocent.

Step-by-step explanation:

From the provided statement.

The statement is: If Smith is guilty, then Jones is innocent.

The converse is: If Jones is innocent, then Smith is guilty.

The combination of a conditional statement and its converse is called biconditional statement.

The biconditional statement contains if and only if phrase between two part of the statement.

Which means the statement and converse both are true.

Therefore, the required biconditional statement is: If Smith is guilty, if and only if Jones is innocent.

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3 years ago

Select all the points that are on the line through (0 5) and (2 8) A.(5 11) B.(5 10) C.(6 14) D.(30 50) E.(40 60)

mihalych1998 [28]

Answer:

Options C. and D. are correct.

Step-by-step explanation:

Let $(x_1,y_1)=(0,5),\,(x_2,y_2)=(2,8)$

Equation of a line is given by $y-y_1=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)$

$y-5=(\frac{8-5}{2-0})(x-0)\\\\y-5=\frac{3}{2}x\\\\2y-10=3x\\3x-2y+10=0$

Put $(x,y)=(5,11)$

$3(5)-2(11)+10=15-22+10=3\neq 0$

Put $(x,y)=(5,10)$

$3(5)-2(10)+10=15-20+10=5\neq 0$

Put $(x,y)=(6,14)$

$3(6)-2(14)+10=18-28+10=0$

Put $(x,y)=(30,50)$

$3(30)-2(50)+10=90-100+10=0$

Put $(x,y)=(40,60)$

$3(40)-2(60)+10=0\\120-120+10=10\neq 0$

So, points $(6,14),\,(30,50)$ satisfy the equation $3x-2y+10=0$

Therefore,

points $(6,14),\,(30,50)$ lie on the line through $(0,5)$ and $(2,8)$

Options C. and D. are correct.

8 0

3 years ago