Answer
6ac−2b−2
Step-by-step explanation:
Let's simplify step-by-step.
4ac+3−2b+2ac−5
=4ac+3+−2b+2ac+−5
Combine Like Terms:
=4ac+3+−2b+2ac+−5
=(4ac+2ac)+(−2b)+(3+−5)
=6ac+−2b+−2
Step-by-step explanation:
Please refer to the attachment
For this case suppose that we have a linear system of equations of the form:
ax + by = c
dx + ey = f
The solution of the system is an ordered pair of the form:
(x, y)
That is, both lines intersect at a point.
The point of intersection in this case is:
(3, 4)
Therefore, the system has one solution.
Answer
the system will have:
one solution
Answer: x = 1 and y = 2
Given:
y = -3x + 5
5x - 4y = -3
Since we are given y, let’s sub it in the second equation.
5x - 4(-3x + 5) = -3
5x + 12x - 20 = -3
17x = 17
x = 1
After finding x, we can now find y.
5(1) - 4y = -3
-4y = -8
y = 2
Checking:
y = -3x + 5
2 = -3(1) + 5
2 = 2
5x - 4y = -3
5(1) - 4(2) = -3
-3 = -3
Answer:

Step-by-step explanation:
So, the function, P(t), represents the number of cells after t hours.
This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.
C)
So, we are given that the quadratic curve of the trend is the function:

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:
![\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5BP%28t%29%5D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B6.10t%5E2-9.28t%2B16.43%5D)
Expand:
![P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]](https://tex.z-dn.net/?f=P%27%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B6.10t%5E2%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B-9.28t%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B16.43%5D)
Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:
![P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]](https://tex.z-dn.net/?f=P%27%28t%29%3D6.10%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5E2%5D-9.28%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5D)
Differentiate. Use the power rule:

Simplify:

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

Multiply:

Subtract:

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.
And we're done!