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3 years ago

8

The distance around a circular flower bed is 36 feet. Jasper wants to put stakes every 8 inches (2/3 of a foot) around the bed.

How many stakes does he need?

1 answer:

White raven [17]3 years ago

4 0

54 stakes. 12" in a foot, 12x36 = 432, 432/8 = 54

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What does n equal? 2=-9n+22-n

velikii [3]

Answer:

n =2

Step-by-step explanation:

2=-9n+22-n

2 = -10n +22

-20 = -10n

n = 2

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Inequalitys please help

mash [69]

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2 years ago

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Michelle's father deposited $1,000 into a savings account when she was born. The annual interest rate is

prohojiy [21]

Answer:

Michelle's age = 16

Step-by-step explanation:

As we know,

Amount = $P (1 + r)^{t}$ where

P = Principal amount

r = rate of interest

t = time

Given ,

P = $1000

r = 4.5 % = $\frac{4.5}{100} = 0.045$

Now,

Given that Amount reaches more than $2000

⇒ $P (1 + r)^{t}$ > 2000

⇒ $1000(1 + 0.045)^{t}$ > 2000

⇒ $(1.045)^{t}$ > 2

Now,

we put the value of t from 0 , 1, 2, ..... untill the above equation does not satisfy

Now,

for t = 0

$(1.045)^{0} = 1 \ngeq 2$

for t = 1

$(1.045)^{1} = 1.045 \ngeq 2$

for t = 2

$(1.045)^{2} = 1.092 \ngeq 2$

for t = 3

$(1.045)^{3} = 1.14 \ngeq 2$

for t = 4

$(1.045)^{4} = 1.19 \ngeq 2$

for t = 5

$(1.045)^{5} = 1.25 \ngeq 2$

for t = 6

$(1.045)^{6} = 1.30 \ngeq 2$

for t = 7

$(1.045)^{7} = 1.36 \ngeq 2$

for t = 8

$(1.045)^{8} = 1.42 \ngeq 2$

for t = 9

$(1.045)^{9} = 1.48 \ngeq 2$

for t = 10

$(1.045)^{10} = 1.55 \ngeq 2$

for t = 11

$(1.045)^{11} = 1.62 \ngeq 2$

for t = 12

$(1.045)^{12} = 1.69 \ngeq 2$

for t = 13

$(1.045)^{13} = 1.77 \ngeq 2$

for t = 14

$(1.045)^{14} = 1.85 \ngeq 2$

for t = 15

$(1.045)^{15} = 1.93 \ngeq 2$

for t = 16

$(1.045)^{16} = 2.02 > 2$

It satisfies at t= 16

∴ we get

Michelle's age = 16

4 0

2 years ago

Please show your work.

levacccp [35]

The amount of money you have is $ 20864.521

<h3><u><em>Solution:</em></u></h3>

Given that you invested $15,000 dollars for 11 years at 3% annual interest compounded continuously.

To find: total amount of money

<em><u>The compound interest formula for compounded continously is given as:</u></em>

$A = p e^{rt}$

Where "p" is the principal

"r" is the rate of interest

"t" is the number of years

Here in this problem, p = 15000

t = 11 years

$r = 3 \% = \frac{3}{100} = 0.03$

<em><u>Substituting the values in formula we get,</u></em>

$A = 15000e^{0.03 \times 11}\\\\A = 15000e^{0.33}\\\\A = 15000 \times 1.390968\\\\A = 20864.521$

Thus the amount of money you have is $ 20864.521

5 0

2 years ago