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Andrews [41]
3 years ago
7

Find an equation for the line that passes through the points (-4, -1) and (6, 3)

Mathematics
2 answers:
Anarel [89]3 years ago
5 0

Answer:

y = (2/5)x + 3/5

Step-by-step explanation:

<u>Points to remember </u>

Equation of the line passing through the poits (x1, y1) and (x2, y2)  and slope m is given by

(y - y1)/(x - x1) = m    where slope m = (y2 - y1)/(x2 - x1)

<u>To find the slope of line </u>

Here (x1, y1) =  (-4, -1) and  (x2, y2) = (6, 3)

Slope = (y2 - y1)/(x2 - x1)

 = (3 - -1)/(6 - -4)

 = 4/10 = 2/5

<u>To find the equation </u>

(y - y1)/(x - x1) = m  

(y - -1)/(x - -4) = 2/5

(y + 1)/(x + 4) = 2/5

5(y + 1) = 2(x + 4)

5y + 5 = 2x + 8

5y = 2x + 3

y = (2/5)x + 3/5

skad [1K]3 years ago
3 0

Answer:

y=2/5x+3/5

Step-by-step explanation:

Use the slope formula to get the slope:

m=4/10

m=2/5

The y intercept is 3/5

The equation is y=2/5x+3/5

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3 years ago
What is the difference? <br> 4/3-7/9
Alecsey [184]

Answer:

Step-by-step explanation:

4/3-7/9=12/9-7/9=5/9.

6 0
3 years ago
Read 2 more answers
I cant figure this one out at all
eduard

Answer:

a. 2^(x-2) = g^(-1)(x)

b. A, B, D

Step-by-step explanation:

the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)

1. replace g(x) with y and solve for x

y = log₂(x) + 2

subtract 2 from both sides to isolate the x and its log

y - 2 = log₂(x)

this text is replaced by the second image -- it was marked as inappropriate

thus, 2^(y-2) = x

replace x with g^(-1)(x) and y with x

2^(x-2) = g^(-1)(x)

2. plug this in to points A, B, C, D, E, and F

A: (2,1)

plug 2 in for x

2^(2-2) = 2⁰ = 1 so this works

B: (4, 4)

2^(4-2) = 2²= 4 so this works

C: (9, 3)

2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work

(5, 8)

2^(5-2) = 2³ = 8 so this works

E: (3, 5)

2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work

F: (8, 5)

2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work

4 0
2 years ago
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