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den301095 [7]
3 years ago
14

Mike goes grocery shopping for baby food for his young daughter. He has a coupon for a popular brand, but as he’s rounding the e

nd of the aisle he sees a display for a new brand of baby food. On the jar it says the baby food is all natural with no preservatives. Because he only wants the best for his daughter, he immediately buys the new brand even though it’s a bit more expensive. Explain what techniques the seller has used to market the new brand of baby food, and if Mike should have taken any additional steps before making his purchase.
Mathematics
2 answers:
Lyrx [107]3 years ago
7 0
People with kids or babies always want them to eat natural foods with no preservation, even if are a bit more expensive than the other available options.What they care about is the quality and health of the kids.So keeping this point in head,most of the brands uses the technique to compete with the other in-market brands. And that's what the shopkeeper did in this case.
Mike should have read the listed ingredients on the baby food jar.I think both of them would have the same,except a few.
Ahat [919]3 years ago
3 0

Answer:

Given is -Because he only wants the best for his daughter, he immediately buys the new brand even though it’s a bit more expensive.

Here, the technique used by the seller is his way and art of using attractive keywords and phrases such as all natural and no preservatives.

Before making the purchase, the step Mike could have considered is, comparing the ingredients of both the baby foods.

It might have been possible that the previous baby food also had no preservatives and it was also natural.

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From what I think;

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Which components are a possible representation of vector w if the magnitude of vector -3w is ||-3w||=15?
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Answer:

<-3,4>

<0,-5>

Step-by-step explanation:

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3|-w| = 3|w| = 15

|w| = \frac{15}{3}

|w| = 5

  • If vector w is represented by <1,-9>

Then |w| = \sqrt{(1)^{2}+(-9)^{2}}=\sqrt{1+81}=\sqrt{82}\neq5 .

Therefore this is not possible.

  • If vector w is represented by <-3,4>

Then |w| = \sqrt{(-3)^{2}+(4)^{2}}=\sqrt{9+16}=\sqrt{25}=5 .

Therefore this is possible.

  • If vector w is represented by <4,5>

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Therefore this is not possible.

  • If vector w is represented by <-5,-3>

Then |w| = \sqrt{(-5)^{2}+(-3)^{2}}=\sqrt{25+9}=\sqrt{34}\neq5 .

Therefore this is not possible.

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Then |w| = \sqrt{(0)^{2}+(-5)^{2}}=\sqrt{0+25}=\sqrt{25}=5 .

Therefore this is possible.

(NOTE : if z vector is represented by <x,y> then |z| = \mathbf{\sqrt{x^{2}+y^{2}}} )

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There is an infinite number of lines that pass through the point (2, 11). Therefore, there is an infinite number of equations. To define a single line, you must have at least two points. One point is not enough.

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