Answer:-3
Step-by-step explanation:
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Technician __Shutdown
Taylor, T___4
Rousche, R _ 3
Hurley, H__ 3
Huang, Hu___2
Gupta, ___ 5
The Numbe of samples of 2 possible from the 5 technicians :
We use combination :
nCr = n! ÷ (n-r)!r!
5C2 = 5!(3!)2!
5C2 = (5*4)/2 = 10
POSSIBLE COMBINATIONS :
TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG
Sample means :
TR = (4+3)/2 = 3.5
TH = (4+3)/2 = 3.5
THu = (4+2) = 6/2 = 3
TG = (4 + 5) = 9/2 = 4.5
RH = (3+3) = 6/2 = 3
RHu = (3+2) /2 = 2.5
RG = (3 + 5) = 8/2 = 4
HHu = (3+2) = 2.5
HG = (3+5) = 8/2 = 4
HuG = (2+5) / 2 = 3.5
Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4
Population mean :
(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4
Population Mean and mean of sample means are the same.
This distribution should be approximately normal.
Answer:
Neither parallel nor perpendicular
Step-by-step explanation:
The lines represented by the equations y = 1x – 5 and 3y + x = -15 are .....
Solve for y in 3y + x = -15.
Answer:
a) k = 0.0001245 /year
b) The Shroud of Turin is 757.52 years old.
Step-by-step explanation:
a) dC/dt = - KC
dC/C = - kdt
Integrating the left hand side from C₀ to C₀/2 and the right hand side from 0 to t(1/2) (where t(1/2) is the radioactive isotope's half life)
In [(C₀/2)/C₀] = - k t(1/2)
In (1/2) = - k t(1/2)
- In 2 = - k t(1/2)
k = (In 2)/t₍₁,₂₎
t(1/2) is given in the question to be 5566 years
k = (In 2)/5566 = 0.0001245 /year
b) dC/C = - kdt
Integrating the left hand side from C₀ to C and the right hand side from 0 to t
In (C/C₀) = - kt
C/C₀ = e⁻ᵏᵗ
C = C₀ e⁻ᵏᵗ
When C = 91% of C₀ = 0.91 C₀, solve for t
0.91 C₀ = C₀ e⁻ᵏᵗ
0.91 = e⁻ᵏᵗ
e⁻ᵏᵗ = 0.91
- kt = In 0.91 = -0.00943
t = - 0.00943/(-0.0001245) = 757.52 years.