Answer:
is that the ixl
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Answer:
g(x) = x² - 4 is already in form of a variable, I.e., x
g(4x) takes another variable, I.e., 4x
Same as before, 4x takes over x:
=> g(4x) = (4x)² - 4
- <em>(</em><em>ax</em><em>)</em><em>²</em><em> </em><em>=</em><em> </em><em>a</em><em>²</em><em>x</em><em>²</em><em>,</em><em> </em><em>where</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>some</em><em> </em><em>arbitrary</em><em> </em><em>constant</em><em>.</em><em> </em>
<h3><u>Answer</u><u>:</u> </h3>
=> g(4x) = 16x² - 4
OR
=> g(4x) = 4{4x² - 1}
Answer:
A. The first graph
Step-by-step explanation:
When you graph these two equations on a graphing calc, you should be able to see one dotted line and one solid, as well as the solutions being mostly in the 1st quadrant.
If 1 and 2 becomes multiplayed gave 3 and 3+3=4 (4-2)+(4-1)= 2+3=4 and 4 is n.
