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Mila [183]
3 years ago
12

The slope of the line is ___.

Mathematics
1 answer:
scoray [572]3 years ago
5 0
There is no image to show the slope

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Each pound of fruit costs $4. Write an expression that shows the total cost of the fruit. Use the variable you identified in que
vovangra [49]

Answer:

$4f

Step-by-step explanation:

Let's assume f represents the number of pounds of fruit.

We need to multiply the number of pounds of fruit by the cost per pound.

This is $f * 4, or in a simpler form, $4f.

6 0
3 years ago
Now dis one dedicated to the girls dem
nirvana33 [79]

Answer:

and dat is onithhh purrrrr.. only of thee most respectfulyy sheesithhh

Step-by-step explanation:

5 0
3 years ago
Write the equation of a line perpendicular to 9xplus7yequals6 that passes through the point ​(9​,negative 7​).
andrew11 [14]

k:\ y=m_1x+b_1\\\\l:\ y=m_2x+b_2\\\\k\ ||\ l\iff m_1=m_2\\\\k\ \perp\ l\iff m_1m_2=-1

We have:

k:\ 9x+7y=6\ \ \ |-9x\\\\7y=-9x+6\ \ \ \ |:7\\\\y=-\dfrac{9}{7}x+\dfrac{6}{9}\to m_1=-\dfrac{9}{7}\\\\l:\ y=m_2x+b\\\\l\ \perp\ k\iff-\dfrac{9}{7}m_2=-1\ \ \ \ |\cdot\left(-\dfrac{7}{9}\right)\\\\m_2=\dfrac{7}{9}\to\ l:\ y=\dfrac{7}{9}x+b

We know. The line <em>l</em> passes throught the point (9, -7). Substitute the coordinates of the poin to the equation of line<em> l </em>:

-7=\dfrac{7}{9}\cdot9+b\\\\-7=7+b\ \ \ \ |-7\\\\b=-14

y=\dfrac{7}{9}x-14\ \ \ \ |\cdot9\\\\9y=7x-126\ \ \ \ |-9y\ |+126\\\\7x-9y=126

Answer: y=\dfrac{7}{9}x-14\to7x-9y=126


7 0
3 years ago
Convert 65,000,000 to scientific notation. (3 points)
yarga [219]

Answer:

6.5x10^7

Step-by-step explanation:

8 0
3 years ago
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
3 years ago
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