The median is 11, so 11 is part of the data set. We have an odd number of values (5) which is why the median is part of the data set.
The mode is 12. The value 12 shows up the most times. Let's say it shows up twice. So far the data set is {11, 12, 12}
Let's introduce two more numbers x and y
The new data set is {x, y, 11, 12, 12}
Add up the five values and then divide by 5. We want this result to be equal to 10
(x+y+11+12+12)/5 = 10
(x+y+35)/5 = 10
x+y+35 = 10*5
x+y+35 = 50
x+y = 50-35
x+y = 15
So we don't know what x or y is, but we know that they must add to 15. So all you have to do is list two numbers that add to 15. One such pair is x = 6 and y = 9. Another pair is x = 7 and y = 8. There are infinitely many possibilities if you can use any real number.
So one possible set is {6, 9, 11, 12, 12}
Another possible set is {7, 8, 11, 12, 12}
Answer:
To simplify first factorize both the numerator and the denominator
For the numerator
5x² + 20xy + 20y²
Factor 5 out
5 ( x² + 4xy + 4y²)
Using a² + 2ab + b² = ( a + b)²
The numerator is
5( x + 2y)²
For the denominator
x² - xy - 6y²
Rewrite -xy as a difference
x² + 2xy - 3xy - 6y²
Factorize
We have the denominator as
( x + 2y)( x - 3y)
So we now have
<h2>
</h2>
Simplify
<h2>
</h2>
We have the final answer as
<h2>
</h2>
Hope this helps you
Answer:
(6)
<u>Isosceles trapezoid</u>
- ∠R and ∠S are supplementary
- ∠S≅∠T, ∠R≅∠V
- m∠S = m∠T = 54°
- m∠R = 180° - 54° = 126°
(9)
<u>Midsegment is half the sum of the base lengths</u>
- ST = 1/2(FP + EQ)
- 3.1 = 1/2(2.7 + EQ)
- 2.7 + EQ = 6.2
- EQ = 6.2 - 2.7
- EQ = 3.5
<h3>
Answer:</h3>
By <em>100 times</em>.
Step-by-step explanation:
Each time something is in Scientific Notation, to every power of 10 something is multiplied by, it grows by 10 times.
By knowing that, if both equations use the same starting number, you can minus the notation section from the larger value, to find the answer.
10^6 - 10^4 = 10^2 ---> 100 times.
Hope that helps, :)
