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ioda
3 years ago
11

Simplify the expression and combine like terms. ​2 (x+6) + 3x + 4

Mathematics
2 answers:
Umnica [9.8K]3 years ago
8 0

Answer:

5x + 16

Step-by-step explanation:

​2 (x+6) + 3x + 4

Simplify:

2x + 12 + 3x + 4

Combine like terms:

(2x + 3x) + (4 + 12) = 5x + 16

anyanavicka [17]3 years ago
5 0

Answer:

5x+16

Step-by-step explanation:

=2x+12+3x+4

=5x+16

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A survey of high schools within a district revealed that for ninth graders, 38% offer no honors classes, 12% offer one
daser333 [38]

Answer:

0.30

Step-by-step explanation:

Find the probability by adding the probabilities together for having two and four honors classes.

25% offer two honors classes and 5% offer four honors classes. Add these together:

25 + 5

= 30

So, there is a 30% probability that the school offers an even number of honors classes.

The correct answer is 0.30.

8 0
3 years ago
1 point) A tank contains 2200 L of pure water. Solution that contains 0.06 kg of sugar per liter enters the tank at the rate 5 L
masya89 [10]

Answer:

Question not complete,

So i will analyse the possible problem

Step-by-step explanation:

A tank contain 2200L

Volume V = 2200L

Solution of 0.06kg/L of sugar

Rate of entry i.e input

dL/dt=5L/min

Let y(t) be the amount of sugar in tank at any time.

But at the beginning there was no sugar in the tank

i.e, y(0)=0, this will be out initial value problem,

The rate of amount of sugar at anytime t is

dy/dt=input amount of sugar - output amount of sugar.

Now,

Then rate of input is

5L/min × 0.06kg/L

Then, input rate= 0.3kg/min

Output rate is

5L/mins × y(t)/2200 kg/L

then, output rate = y(t)/440 kg/min

Now then,

dy/dt=input rate -output rate

dy/dt=0.3-y/440

Cross multiply through by 400

400dy/dt=120-y

Using variable separation

400/(120-y) dy = dt

∫400/(120-y) dy = ∫dt

-400In(120-y)=t +C

In(120-y)=-t/400+C/400

C/400 is another constant, let say B

In(120-y)=-t/400+B

Take exponential of both side

120-y(t)=exp(-t/400+B)

120-y(t)=exp(-t/400)exp(B)

exp(B) is a constant let say C

-y(t)=Cexp(-t/400)-120

y(t)=120-Cexp(t/400)

Now, the initial condition

a. At the start the mass of sugar in the water is 0 because it is just pure water at start.

Therefore y(0)=0,

b. Applying this to y(t)

y(t)=120-Cexp(-t/400)

y=0, t=0

0=120-Cexp(0)

0=120-C

C=120

Therefore,

y(t)=120 - 120exp(-t/400)

Let know the mass rate as t tends to infinity

At infinity

exp(-∞)=1/exp(∞)=1/∞=0

Then,

The exponential aspect tend to 0

Then, y(t)=120 as t tend to ∞

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%2096" id="TexFormula1" title="\sqrt 96" alt="\sqrt 96" align="absmiddle" class="latex-
klasskru [66]

Answer:

If it is \sqrt{96} \sqrt{96} then it is the solution \sqrt{96} \sqrt{96}  = 96 because the square root of an expression multiplied by itself gives that expression.

7 0
3 years ago
Which quadrilateral’s diagonals do not create a 90° angle at its intersection?
Shtirlitz [24]
A Rhombus and a Kite are the same thing they are the answer
4 0
3 years ago
Read 2 more answers
A tube-feeding formula is administered to a patient via Gastrostomy at 75
melomori [17]

Answer:

97.5ml protein

Step-by-step explanation:

20hr * 75ml/hr = 1500ml

1500ml * .065 = 97.5ml protein

8 0
3 years ago
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