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3 years ago

Which of the following is equivalent to 140 centiliters?

2 answers:

6 0

The answer is C) because one litre=100 centiliters, and one kilolitre=one litre which means that one kilolitre =100000 centiliters
So 140 centiliters are 140 divided by 100000 kiloliters=0.00140 kiloliters

Fudgin [204]3 years ago

5 0

The <em><u>correct answer</u></em> is:

C.) 0.00140 kiloliters

Explanation:

To convert this, we can use a metric conversion chart:

Kilo- Hecto- Deca- base deci- centi- milli-

Starting with 140 centiliters, converting to deciliters moves to the left 1 place; this moves the decimal to the left one, making it 14.0 deciliters.

Converting to liters, we move to the left 2 places; this moves the decimal to the left two, making it 1.40 liters.

Converting to milliliters, we move to the right 1 place; this moves the decimal to the right one, making it 1400 milliliters.

Converting to kiloliters, we move to the left 5 places; this moves the decimal left 5, making it 0.00140 kiloliters.

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An airplane is traveling at a speed of 240 miles/hour with a bearing of 110°. The wind velocity is 56 miles/hour at a bearing of

vodka [1.7K]

Answer:

Actual speed = 288 miles per hour

Actual direction angle = $116.38^\circ$

Step-by-step explanation:

"Bearing" is the relative position of an object outside the plane compared to the position of the plane.

Heading the the direction the nose of the plane is pointing.

Course is the direction that pilot wants the plane to go.

Wind direction is always the direction the wind is blowing from.

The airplane is traveling at a speed of 240 miles/hour with a bearing of 110°.

If the plane is traveling with a bearing of 110° and the wind is blown at a bearing of 325°.

$325^{\circ}- 110^{\circ} =225^{\circ}$

$215^{\circ}- 180^{\circ} =35^{\circ}$

The Ground speed will be in excess of the airspeed and true direction will be south if the indicated heading.

The tailwind component is:

$56 cos (35^\circ)$

And the cross wind component is:

$56 sin (35^\circ)$

And that is,

$C^2 = (286)^2 + (32)^2$

$c = 288$

So the actual speed of the plane is 288 miles per hour.

The deviation in the direction is:

Let the direction angle be 'x'.

$x = tan ^{-1}\left ( \frac{32}{286} \right )=6.38^\circ$

So the actual direction angle is $110^\circ+ 6.38^\circ=116.38^\circ$ .

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3 years ago

Test scores are normally distributed with a mean of 500. Convert the given score to a z-score, using the given standard deviatio

Bond [772]

Answer:

The percentage of students who scored below 620 is 93.32%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 500, \sigma = 80$

Percentage of students who scored below 620:

This is the pvalue of Z when X = 620. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{620 - 500}{80}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

The percentage of students who scored below 620 is 93.32%.

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3 years ago

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Celsius = (Fahrenheit - 32) x 5/9

C(76.1) = (76.1 - 32) x 5/9
= (44.1) x 5/9
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Therefore, 76.1 degrees Fahrenheit = 24.5 degrees Celsius.

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x=[5,7]

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