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lakkis [162]
3 years ago
9

Which algebraic expression is equivalent to the expression below

Mathematics
2 answers:
laila [671]3 years ago
8 0
The answer is 1) 33x + 68
djyliett [7]3 years ago
4 0
21x + 84 + 12x - 16
33x + 68

The correct answer is 1.) 33x + 68.
Hope this helps!
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This is very easy!!​
Olenka [21]

Answer:

product

Step-by-step explanation:

hope it helps

5 0
2 years ago
Read 2 more answers
What is the asymptote of g(x)= 4 (1/3) - 2
Nataly [62]

Answer: X=2

Step-by-step explanation:

Assuming the function is

All logarithmic functions, despite their base, has a vertical asymptote at argument = 0.

That is not changed by the vertical stretching made by the 4 which multiplies the logarithm nor  the vertical shift made by the +5.

In this case the argument is x - 2, then the vertical asymptote is:

x - 2 = 0

8 0
2 years ago
Find a solution to the linear equation −2x−2y=8 by filling in the boxes with a valid value of x and y.Provide your answer below:
inna [77]

Given

-2x-2y=8

To find a solution for the linear equation, the first step is to write the equation in slope-intercept form:

-Pass the x-term to the right side of the equation by applying the opposite operation to both sides of the equal sign:

\begin{gathered} -2x+2x-2y=8+2x \\ -2y=2x+8 \end{gathered}

-Divide both sides by -2:

\begin{gathered} \frac{-2y}{-2}=\frac{2x}{-2}+\frac{8}{-2} \\ y=-x-4 \end{gathered}

Once you have expressed the equation of the line in slope-intercept form, replace it with any value for x and calculate the corresponding value of y, for example, x=2

\begin{gathered} y=-(2)-4 \\ y=-2-4 \\ y=-6 \end{gathered}

One solution for the linear equation is x=2 and y=-6, you can check the solution by replacing the values on the original equation, with both values the result should be 8:

\begin{gathered} -2x-2y \\ -2\cdot2-2\cdot(-6) \\ -4+12=8 \end{gathered}

As you can see the values are a valid solution for the linear equation.

So the solution is:

-2(2)-2(-6)=8

6 0
1 year ago
There is concern that increased industrialization may be increasing the mineral content of river water. Ten years ago, the silic
Tema [17]

Answer:

a) P value = 0.0013

b) No, it is not plausible that the silicon content of the water is no greater than it was 10 years ago

Step-by-step explanation:

The null hypothesis here is “Mean is equal to 5” while alternate hypothesis is that “Mean is greater than 5”

Given  

Mean = 5, x’ = 5.4 and sigma = 1.2 and n = 85

Z = x-u’/sigma/sqrt n

Substituting the given values, we get –  

Z = 3.02

A) P value = 0.0013 which is less than 0.05 and thus we will reject the null hypothesis

B) There is enough evidence to reject the null hypothesis  

6 0
3 years ago
An exponential function is expressed in the form y=axb^x. The relation represents a growth when
RSB [31]
<span>y=axb^x. 
when x>0 and not equal to 0</span>
6 0
3 years ago
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