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serious [3.7K]
2 years ago
11

Solve the exponential equation by the method of relating the​ bases, first rewriting the equation in the form

Mathematics
1 answer:
Nookie1986 [14]2 years ago
6 0

Answer:

  x = 1/3

Step-by-step explanation:

Both bases can be written as powers of 6.

  36^x = (1/6)^(x-1) . . . . . . given

  (6^2)^x = (6^-1)^(x -1) . . . . . bases as powers of 6

  6^(2x) = 6^(-x+1) . . . . . . . . . simplify exponents

  2x = -x +1 . . . . . . . . . . . . . . . .equate exponents of the same base

  3x = 1 . . . . . . . add x

  x = 1/3 . . . . . divide by 3

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(1 point) A particle starts at the point P=(−2,−1,3)P=(−2,−1,3) when t=0t=0 and moves along a straight line toward Q=(−4,0,6)Q=(
Ahat [919]

Answer:

The position is given by r(t) =  (-2 -t √14, 1 + √3.5, 3 + 3√3.5)

Step-by-step explanation:

The direction is given by the difference between the starting point and the end point, thus it is (-4,0,6)-(-2,-1,3) = (-2,1,3). The norm of this vector is        √( (-2)²+1²+3²) = √14 = 3.7416 secons

Since the speed is 7 cm/sec, we need to multiply this vector by 7/√14 = √3.5 in order to obtain how much does the particle advance each second.

As a consecuence, it advances (-2,1,3) * √3.5 = (- √14, √3.5, 3 √3.5)

And, as a result, the position after t seconds is given by the function

r(t) = (-2,1,3) + t (-√14, √3.5, 3 √3.5) = (-2 -t √14, 1 + √3.5, 3 + 3√3.5)

8 0
3 years ago
PLEASE HELP! (WILL GIVE BRAINLIEST FOR RIGHT ANSWER)
dimaraw [331]

Answer:

-41.29*  10^-7

Step-by-step explanation:

You would change the order of the numbers by multiplying -4.44 and 9.3 together and multiply 10^-7 and 10^0. Which would now look like this:

(-4.44* 9.3)* (10^-7* 10^0)

-4.44* 9.3= -41.292 and 10^-7* 10^0= 1* 10^-7. So now the equation would look like this:

-41.292* 10^-7

Then round -41.292 to 2 decimal places which would be -41.29.

-41.29*  10^-7

That's the answer. I hope this helps!

6 0
3 years ago
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