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eimsori [14]
3 years ago
10

Explain why any of the four operations (+-x / )placed between the two terms 5 and-3/(radical sign) 8 will result in an irrationa

l number. Please help me!!! It’s due today
Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0

Answer:

5 + (-3/2√2) = irrational number

5 - (-3/2√2) = irrational number since we have  √2

Step by step explanation

Here the given two numbers are 5 and -3/√8.

Here we can rewrite √8 = √2√4

Which is 2√2.

So √8 = 2√2, where √2 is an irrational number.

-3/√8 = -3 / 2√2 = =3/ 2√2 is an irrational number.

When you add, subtract, multiply and divide a whole number (5) with an irrational number (-3/2√2) is always an irrational number.

Therefore, when you do the operations with 5 and -2/2√2 always result in irrational number.

Hope you will understand the concept.

Thank you.

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A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
If 4 raffle tickets is 6 dollars how much is 1 raffle ticket
sertanlavr [38]
4/6 = 1/x cross multiple so x= 1.5 dollars
8 0
3 years ago
It was -5 degrees Celsius in Copenhagen and -12 degrees Celsius in Oslo. Which city was colder? *
PtichkaEL [24]

Answer: Oslo was colder

Step-by-step explanation: The other one was -5 and this won is -12 so Oslo is colder!! Hope it helped! :)

8 0
3 years ago
Mrs. Simmons gave a history test worth 92 points. There were only two types of questions on it: 2-point true/false questions and
SVETLANKA909090 [29]

Answer:

There are 8 true/false questions and 26  fill-in-the-blank questions.

Step-by-step explanation:

Let "t" be the number of 2-point true/false questions and "f" the number of 5-point fill-in-the-blank questions.

Mrs. Simmons gave a history test worth 92 points. Symbollically,

2 t + 5 f = 92   [1]

There were a total of 34 questions in the test. Symbollicaly,

t + f = 34

t = 34 - f   [2]

If we replace [2] in 1, we get

2 (34 - f) + 5 f = 92

68 - 2 f + 5 f = 92

3 f = 24

f = 8

We replace f = 8 in [2],

t = 34 - 8 = 26

There are 8 true/false questions and 26  fill-in-the-blank questions.

7 0
3 years ago
A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit
Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}  

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • p is the probability of a success on a single trial.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The expected number of <u>trials before q successes</u> is given by:

E = \frac{q(1-p)}{p}

The variance is:

V = \frac{q(1-p)}{p^2}

In this problem, 0.2 probability of a finding a person who attended the last football game, thus p = 0.2.

Item a:

  • None of the first three attended, which is P(X = 0) when n = 3.
  • Fourth attended, with 0.2 probability.

Thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512

0.2(0.512) = 0.1024

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c:

  • One person, thus q = 1.

The expected value is:

E = \frac{q(1-p)}{p} = \frac{0.8}{0.2} = 4

The variance is:

V = \frac{0.8}{0.04} = 20

The expected number of people is 4, with a variance of 20.

A similar problem is given at brainly.com/question/24756209

3 0
2 years ago
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