3 years ago

The legs of an isosceles triangle have lengths x+1 and -x+7 . The base has length 3x-3. What is the length of the base?

1 answer:

mote1985 [20]3 years ago

6 0

The only thing I'm a little unclear on here is what you mean by
the "legs" of an isosceles triangle.

I'm going to assume that your isosceles triangle is standing on
the side you call the "base", and the "legs" are the two slanty ones,
standing up, which are the two equal sides.

With that set-up,    x + 1 = -x + 7

Add x to each side:    2x + 1 = 7

Subtract 1 from each side: 2x      = 6

Divide each side by 2 : x   =    3

Finally, if the base is (3x - 3), then that's (3·3 - 3) = 6 .

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Priya and Han both factored the number 80. Priya says they should both get the same answer even if they started with different f

meriva

Answer:

Priya is right.

Step-by-step explanation:

The factors of 80 is 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

The factor pairs of 80 are

1 x 80, 2 x 40, 4 x 20, 5 x 16 and 8 x 10

If Priya picks 2 x 40, then it's prime factorisation will be, 2 x 2 x 2 x 2 x 5 = 2⁴ x 5.

If Han picks, 5 x 16 = 5 x 2 x 2 x 2 x 2 = 5 x 2⁴ = 2⁴ x 5. This is the same.

Therefore, Priya is correct, because the factors of 80 are always the same, therefore which ever you start with, you'd always get the same answer.