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nasty-shy [4]
3 years ago
7

The legs of an isosceles triangle have lengths x+1 and -x+7 . The base has length 3x-3. What is the length of the base?

Mathematics
1 answer:
mote1985 [20]3 years ago
6 0

The only thing I'm a little unclear on here is what you mean by
the "legs" of an isosceles triangle. 

I'm going to assume that your isosceles triangle is standing on
the side you call the "base", and the "legs" are the two slanty ones,
standing up, which are the two equal sides.

With that set-up,                       x + 1 = -x + 7

Add  x  to each side:               2x + 1 =        7

Subtract  1  from each side:    2x      =        6

Divide each side by  2 :            x       =        3


Finally, if the base is  (3x - 3), then that's  (3·3 - 3)  =  6 .

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Divide using synthetic division. ( x^4-12x^2-9)/(x+3)
Firdavs [7]

Answer:

x^3 - 3x^2 - 3x + 9 + (-36/(x+3))

OR

x^3 - 3x^2 - 3x + 9 - (36/(x+3))

Step-by-step explanation:

First set the divisor equal to 0:

x + 3 = 0

Subtract 3 from both sides

x = -3

This is what you'll divide the dividend by in synthetic division.

Take the coefficents of each term in the dividend. Do not forget the 0 placeholders:

x^4 + 0x^3 - 12x^2 + 0x -9

Coefficents: 1. 0.  -12. 0 -9.

Please see the image for the next steps.

The remainder is -36. Put the remainder over the divisor and add it to the polynomial (shown in image)

-36/(x+3)

6 0
3 years ago
-3.1+7-7.4x=1.5x-6(x-3/2)
Ronch [10]

Answer:

1.76

Step-by-step explanation:

3.9-7.4x=-4.5x+9

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x=1.758 or 1.76

I hope this helps, if not i'm sorry.

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Solve each system by elimination.<br> 3x + 2 =10 , 6 +4y = 15
NISA [10]

By elimination, the system of equations, 3x + 2y = 10 , 6x + 4y = 15, has no solutions.

A system of equations is a set of two or more equations which includes common variables. To solve system of equations, we must find the value of the unknown variables used in the equations that must satisfy all the equations.

There are three methods that can be used to solve system of equations.

1. Elimination

2. Substitution

3. Graphing

Using the elimination method, given two equations in x and y, a variable should be eliminated by adding/subtracting the two equations.

First, multiply the first equation by 2.

3x + 2y = 10 ⇒ 6x + 4y = 20     (equation 1)

6x + 4y = 15     (equation 2)

Since the new equation of equation 1 has the same coefficients with those in equation 2, but different constants, then the two lines are in parallel.

Hence, the system of equations has no solutions.

Learn more about solving systems of equations by elimination here: brainly.com/question/28405823

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