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3 years ago

PLS HELP Complete the table so that the numbers in each column represent the coordinates of a point on the graph

Mathematics

1 answer:

Natasha2012 [34]3 years ago

4 0

Answer:

1 is 1/2 5 is 2 1/2 and 7 would be 3 1/2

Step-by-step explanation:

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Find cot theta if 180° < theta < 270° and cos theta = - sqrt 3/2

avanturin [10]

Answer:

cot theta = -√3

Step-by-step explanation:

we are given that cos theta = - √3/2 within the range 180° < theta < 270° and

since cos theta = adj/hyp

adj = - √3

hyp = 2

Get the opposite using the pythagoras theorem

hyp^2 = opp^2 + adj^2

2² = opp² + (-√3)²

4 = opp² + 3

opp² = 4-3

opp² = 1

opp = 1

tan theta = opp/adj

tan theta = - 1/√3

Recall that cot theta = 1/tan theta

cot theta = 1/(-1/√3)

cot theta = -√3

8 0

3 years ago

Solve by completing the square, please help

Talja [164]

Answer:

x = 4 + √ 38

Step-by-step explanation:

6 0

2 years ago

Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°

mote1985 [20]

Answer:

$sin(2\theta)=\frac{\sqrt{35} }{18}$

Step-by-step explanation:

Recall the formula for the sine of the double angle:

$sin(2\theta)=2*sin(\theta)*cos(\theta)$

we know that $cos(\theta)=\frac{3}{18}$ , and that $\theta$ is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what $sin(\theta)$ is:

$cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }$

With this information, we can now complete the value of the sine of the double angle requested:

$sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}$

6 0

3 years ago

The graph of f(x)=ax^2 is narrower than the graph of g(x)=dx^2 when a<d

Lynna [10]

Answer:

Step-by-step explanation:

as given in question that a > 0 so

if we put a=1

we get g(x) = f(x)

now put a =2

we get

g(x) = 2 f(x)

here we can see that g(x) would always be greater than or equals to f(x)

so we can say that the graph of g(x) will never be narrower than graph of g(x)

4 0

3 years ago

Solve and model 7/10-3/10

sergij07 [2.7K]

Hello,

$\frac{7}{10} - \frac{3}{10}$ = 2/5

Solution.

<span> $\frac{7}{10} - \frac{3}{10}$ = The denominators are the same so you subtract the numerator. Your answer should be </span> $\frac{4}{10}$ simplified your answer is $\frac{2}{5}$ .

Have A Good Day!

7 0

3 years ago