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love history [14]
2 years ago
10

I really need help understanding this question! thank you!

Mathematics
2 answers:
aleksandr82 [10.1K]2 years ago
8 0

Answer:

\boxed{\text{6 and 7}}

Step-by-step explanation:

1. Set up the equation

        Let x = the first integer. Then

         x + 1 = the next integer

     x(x + 1) = the product of the integers

     x(x + 1) = 42

       x² + x = 42     Distributed the x

x² + x - 42 = 0

2. Solve for x

(x + 7)(x - 6) = 0            Factored the quadratic

x + 7 = 0     x - 6 = 0     Applied zero product rule

     x = -7         x = 6     Solved the binomials

We reject x = -7, because x must be positive

    x = 6

x + 1 = 7

\text{The two consecutive positive integers are \boxed{\textbf{6 and 7}}}

Check:

6(6+ 1) = 42

   6(7) = 42

     42 = 42

OK.

klasskru [66]2 years ago
4 0

n(n+1)=42\\n^2+n-42=0\\n^2-6n+7n-42=0\\n(n-6)+7(n-6)=0\\(n+7)(n-6)=0\\n=-7 \vee n=6

-7 is not positive

n=6\\n+1=7

The numbers are 6 an 7.

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Step-by-step explanation:

We have been given an equation x^2+3x-10=0. We are asked to find the solutions of our given equation.

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