A pentagonal prism is cut by a plane perpendicular to the base. What is the shape of the cross section that is formed?

Mathematics

1 answer:

rewona [7]2 years ago

5 0

Answer: A rectangle

Note: I am a bit confused between A), B), and C), but the answer I am going for is C).

Step-by-step explanation:

By definition, a cross-section is the intersection of a plane and a body of three dimensions.

A pentagonal prism has a pentagon as its base. and its lateral faces are rectangles.

If a plane perpendicular cuts the pentagonal prism to the base, this means that the plane is parallel to lateral faces, then, the shape of the cross-section that is formed is also a rectangle.

You might be interested in

42×4/7 how do this problem

vlada-n [284]

Convert to:

42 4 168
---- x ---- = ------
1 7 7

5 0

2 years ago

Please help me with this question

Aleks [24]

Answer:

y=75x+1

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?

Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Reciprocals

Algebra II

Log/Ln Property: $ln(\frac{a}{b} ) = ln(a) - ln(b)$

Calculus

Derivatives

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative of Ln: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

$ln(\frac{2x-1}{x-1} )=t$

Step 2: Differentiate

Rewrite: $t = ln(\frac{2x-1}{x-1})$
Rewrite [Ln Properties]: $t = ln(2x-1) - ln(x - 1)$
Differentiate [Ln/Chain Rule/Basic Power Rule]: $\frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1$
Simplify: $\frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}$
Rewrite: $\frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}$
Combine: $\frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}$
Reciprocate: $\frac{dx}{dt} = -(2x-1)(x-1)$
Distribute: $\frac{dx}{dt} = (1-2x)(x-1)$