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Svetllana [295]
3 years ago
6

I've been stuck on this question for a while now, I need help!

Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0
In order to solve it you must make each component negative. Multiply them by negative one!

M < 2

Now which numbers would satisfy it? M is less than two... so, m could be one, or any negative number, yeah?

Multiply by negative one. - M and -2 are what you have. If it were one... negative one is less than negative two. Turns out M is less than two.

M < 6

M is less than six. It could be 1, 2, 3, 4, or 5.

-M and -6

Is negative 3 less than -6? All of the numbers are! So, m is actually less than 6


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Suppose that 40 deer are introduced in a protected wilderness area. The population of the herd
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The horizontal asymptote of the function is the minimum number of deer in the area.

  • The equation of horizontal asymptote is: \mathbf{y = 40}
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The equation is given as:

\mathbf{f(x) = \frac{40 + 2x}{1 + 0.05x}}

Expand the numerator

\mathbf{f(x) = \frac{40(1 + 0.05x)}{1 + 0.05x}}

Cancel out the common factor

\mathbf{f(x) = 40}

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\mathbf{y = 40}

The horizontal asymptote means that, the number of deer will never be less than 40

Read more about horizontal asymptotes at:

brainly.com/question/4084552

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D 0.61

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