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Svetllana [295]
3 years ago
6

I've been stuck on this question for a while now, I need help!

Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0
In order to solve it you must make each component negative. Multiply them by negative one!

M < 2

Now which numbers would satisfy it? M is less than two... so, m could be one, or any negative number, yeah?

Multiply by negative one. - M and -2 are what you have. If it were one... negative one is less than negative two. Turns out M is less than two.

M < 6

M is less than six. It could be 1, 2, 3, 4, or 5.

-M and -6

Is negative 3 less than -6? All of the numbers are! So, m is actually less than 6


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You discover that you are over serving a dish because customers keep taking a third of it home. If the dish requires 4 ingredien
devlian [24]

Answer:

4 parts

Step-by-step explanation:

If the total number of parts is 12 and you want to reduce the dish to two-thirds its current size, the number of parts that will be reduced is (1 - 2/3) = 1/3

To reduce 1/3 of the 12 parts, you need to multiply 12 by 1/3 to know how many parts is that:

12 * 1/3 = 12/3 = 4

You need to subtract 4 parts. If you have 4 ingredients, you can remove 1 part of each, so each ingredient now will have 2 parts.

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Step-by-step explanation:

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3 years ago
the axis of symmetry for the graph of the function is f(x) = 1/4x2 bx 10 is x = 6. what is the value of b?
Lady bird [3.3K]

we have

f(x)=\frac{1}{4} x^{2} +bx+10

This is a vertical parabola open upward

The axis of symmetry is equal to the x-coordinate of the vertex

The vertex is the point (h,k)

the equation of the axis of symmetry is x=h

In this problem

x=6

so the x-coordinate of the vertex is h=6

<u>Convert the quadratic equation in vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-10=\frac{1}{4} x^{2} +bx

Factor the leading coefficient

f(x)-10=\frac{1}{4}(x^{2} +4bx)

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-10+b^{2}=\frac{1}{4}(x^{2} +4bx+4b^{2})

Rewrite as perfect squares

f(x)+(b^{2}-10)=\frac{1}{4}(x+2b)^{2}

f(x)=\frac{1}{4}(x+2b)^{2}-(b^{2}-10)

remember that

h=6

so

(x+2b)=(x-6)

2b=-6

b=-3

substitute in the equation

f(x)=\frac{1}{4}(x-6)^{2}-((-3)^{2}-10)

f(x)=\frac{1}{4}(x-6)^{2}+1

therefore

<u>the answer is</u>

b=-3


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4 years ago
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The regular price of a camera is 97.99. the sale price is 83.30. What is the discount?
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