We know that sin2x=2sinxcosx
(search the net for proof if you wish)
So the original equation becomes
2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get:
sinx(2cosx-1)=0
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2
sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer
Answer:
a) Option C) The score was 2.49 standard deviations higher than the mean score in the class.
b) 2.3%
Step-by-step explanation:
a) We are given that the distribution of test grades is a bell shaped distribution that is a normal distribution.
Formula:


Option C) The score was 2.49 standard deviations higher than the mean score in the class.
b) The z-score for a particular score is -2.
We have to evaluate
P(z < -2)
Calculating the value from normal z-table.

Thus, 2.3% of of the class scored lower than my friend.
Answer:
m∠SQR = 74°
Step-by-step explanation:
Points P, Q and R are collinear.
Therefore, angles PQR and angle RQS are the linear pair of angles.
Since linear pair of angles are supplementary angles.
m∠PQR + m∠RQS = 180°
By substituting the measures of the given angles,
(3m + 1) + (2m + 4) = 180
5m + 5 = 180
5m = 180 - 5
5m = 175
m = 
m = 35
Since, m∠SQR = (2m + 4)°
= (2×35) + 4
= 74°
Therefore, m∠SQR = 74° is the answer.