A tortoise walks 3 inches in 1 second. How many feet per second can the tortoise walk?

Suppose that 16 inches of wire costs 80 cents. At the same rate, how much in cents will 11 inches of wire cost

irga5000 [103]

Find the cost of 1 inch by dividing 80 cents by 16 inches, then multiply that cost by 11:

0.80 / 16 = 0.05 per inch.

11 inches x 0.05 = 0.55

It will cost 55 cents.

5 0

3 years ago

Read 2 more answers

A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte

AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

$\angle SPR$ =Angle subtended by the statue to where you are standing.

$\angle x=\angle RPQ$ = which is unknown.

Let us begin solving now. The first step is to find the angle $\angle x$ which can be found by using the following trigonometric ratio in $\Delta PQR$ :

$tan(x)=\frac{RQ}{PQ} =\frac{21}{57}$

Which gives $\angle x$ to be:

$\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}$

Now, we know that $\angle x$ and $\angle SPR$ can be added to give us the complete angle $\angle SPQ$ in the right triangle $\Delta SPQ$ .

We can again use the tan trigonometric ratio in $\Delta SPQ$ to solve for the height of the statue, h.

This can be done as:

$tan(\angle SPQ)=\frac{SQ}{PQ}$

$tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}$

$tan(27.32^0)=\frac{h+21}{57}$

$\therefore h+21=57tan(27.32^0)$

$h\approx8.45 ft$

Thus, the height of the statue is approximately, 8.45 feet.

3 0

3 years ago

6. Ed drives from Jefferson to Holden, a distance of 250 miles. He then travels on to

andreev551 [17]

Answer:

The constant speed with Ed is travelling is 60 mile per hour

Step-by-step explanation:

Given as :

The distance cover to travel from Jefferson to Holden is (D1) 250 miles

The distance cover to travel from Holden to Paxton is (D2) 50 miles

Total time taken to complete entire journey = T = 5 hours

Let The constant speed of Ed = S mph

Time = $\frac{Distance}{Speed}$

Or, Time = $\frac{D1}{S}$ + $\frac{D2}{S}$

Or, 5 hour = $\frac{250}{S}$ + $\frac{50}{S}$

Or, 5 × S = 250 + 50

So, 5 × S = 300

∴ S = $\frac{300}{5}$

I.e S = 60 mph

Hence , The constant speed with Ed is travelling is 60 mile per hour Answer

6 0

4 years ago

Find the constant of variation (k) where y varies directly with x. y = 2, when<br> X = 6.

ExtremeBDS [4]

Answer:

The graph below models the value of a $20,000 car t years after it was purchased.

Value of Car

A graph titled Value of Car has years on the x-axis and Dollars on the y-axis. A line curves down and goes through points (0, 20,000), (4, 10,000), and (14, 2,000).

Which statement best describes why the value of the car is a function of the number of years since it was purchased?

Each car value, y, is associated with exactly one time, t.

Each time, t, is associated with exactly one car value, y.

The rate at which the car decreases in value is not constant.

There is no time, t, at which the value of the car is 0.

Step-by-step explanation:

7 0

3 years ago

- m + 62m2 + 1200<br> simplified

Gekata [30.6K]

3(41x+400) simplified = 123x+1200

3 0

3 years ago

Read 2 more answers