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Lana71 [14]
4 years ago
11

Solve the equation: Sin2x - Sinx = 0

Mathematics
1 answer:
Viktor [21]4 years ago
5 0
We know that sin2x=2sinxcosx 
(search the net for proof if you wish) 

So the original equation becomes

2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get: 

sinx(2cosx-1)=0 
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2

sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer

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1/15.999=x/54.5<br> Does anyone know what to do? I keep getting the answer wrong.
kkurt [141]
Hello!

First, let's write the problem.
\frac{1}{15.999}=\frac{x}{54.5}
Let's switch sides now, otherwise, we are going to end up doing it later.
\frac{x}{54.5}=\frac{1}{15.999}
Multiply both sides by 54.5.
\frac{x}{54.5} *54.5 =\frac{1}{15.999}*54.5
We could also rewrite that as,
\frac{54.5x}{54.5}=\frac{1\cdot \:54.5}{15.999}
Simplify.
\frac{54.5x}{54.5}=x
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x=3.40646\dots
That would be our final answer, we could round it to.
x ≈ 3.40

You can feel free to let me know if you have any questions regarding this!
Thanks!

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