All categories

3 years ago

Solve . 3 1/5 Equals Y - 12/25A. 3 17/25 B. 4 17/25C. 3 1/5D. 3 7/25

1 answer:

6 0

3 1/5 = y - 12/25

Make 3 1/5 an improper fraction.

16/5 = y - 12/25

Add 12/25 to both sides.

16/5 + 12/25 = y

Make a common denominator.

80/25 + 12 / 25 = y

92 / 25 = y

3 17/25 = y

Hope this helps!

You might be interested in

7,014 + 2,415 + 774 + 30 = _____

Cloud [144]

9,459

8,444

23,963

9,304

3,719

7 0

3 years ago

Can someone help me with this question?

arlik [135]

Try this solution:

1. m∠A=m∠L; m∠B=m∠M and m∠C=m∠N;

2. m∠B=m∠M=35° and m∠C=m∠N=95°;

3. m∠A=m∠L=180°-(m∠B+m∠C)=180-35-95=50°

answer: 50°

5 0

3 years ago

We're dividing by 4 ÷0.96

Debora [2.8K]

Answer: 4 ÷ 0.96 = 4.16666666667

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

SOLVE FOR X please help !!!!!!!!!!!

Julli [10]

think of it as half a circle which all equals up to 180 degrees

subtract 180 degrees with 62 degrees which 62 degrees is in the problem.

180-62=118 degrees

so your answer is C) 118 degrees

hope that helped you out:)

Please mark my answer brainiest

8 0

2 years ago

Mason plays a game by flipping two fair coins.He wins the game if both coins land facing heads up. If Mason plays 200 times, how

blagie [28]

Answer:

Therefore Mason would be expected to win 50 times.

Step-by-step explanation:

i) probability of flipping a head for a fair coin is $\frac{1}{2}$

ii) probability of flipping two fair coins is = $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

iii) Therefore if Mason plays 200 times he would be expected to win

= $\frac{1}{4} \times 200 = 50\hspace{0.1cm} times.$

7 0

3 years ago