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3 years ago

Solve . 3 1/5 Equals Y - 12/25A. 3 17/25 B. 4 17/25C. 3 1/5D. 3 7/25

1 answer:

6 0

3 1/5 = y - 12/25

Make 3 1/5 an improper fraction.

16/5 = y - 12/25

Add 12/25 to both sides.

16/5 + 12/25 = y

Make a common denominator.

80/25 + 12 / 25 = y

92 / 25 = y

3 17/25 = y

Hope this helps!

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Show the work please

Kay [80]

Answer:

1) (x + 3)(3x + 2)

2) x= +/-root6 - 1 by 5

Step-by-step explanation:

3x^2 + 11x + 6 = 0 (mid-term break)

using mid-term break

3x^2 + 9x + 2x + 6 = 0

factor out 3x from first pair and +2 from the second pair

3x(x + 3) + 2(x + 3)

factor out x+3

(x + 3)(3x + 2)

5x^2 + 2x = 1 (completing squares)

rearrange the equation

5x^2 + 2x - 1 = 0

divide both sides by 5 to cancel out the 5 of first term

5x^2/5 + 2x/5 - 1/5 = 0/5

x^2 + 2x/5 - 1/5 = 0

rearranging the equation to gain a+b=c form

x^2 + 2x/5 = 1/5

adding (1/5)^2 on both sides

x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2

(x + 1/5)^2 = 1/5 + 1/25

(x + 1/5)^2 = 5 + 1 by 25

(x + 1/5)^2 = 6/25

taking square root on both sides

root(x + 1/5)^2 = +/- root(6/25)

x + 1/5 = +/- root6 /5

shifting 1/5 on the other side

x = +/- root6 /5 - 1/5

x = +/- root6 - 1 by 5

x = + root6 - 1 by 5 or x= - root6 - 1 by 5

4 0

3 years ago

Heather finished the 12-kilometer race in 2 hours. If Heather kept her pace constant, what was her rate? A. 24 km/hr. B. 14 km/h

andriy [413]

Answer: D, 6km/hr.

Step-by-step explanation:

Heather can finish a 12-kilometer race in 2 hours, and now we have to find how many kilometers she can ride/run at in 1 hour.

How many hours can Heather run in 1 hour? To solve that, we can use the equation 12 ÷ 2.

12 ÷ 2 = 6.

Therefore, if Heather keeps her pace constant, then her rate will be 6km/hr, or D.

7 0

3 years ago

I am the amount left over when a number canot be divided equally answer quick

Kryger [21]

Answer:

Remainder

Step-by-step explanation:

When a number can't be divided equally, there's an amount leftover. The leftover number is called a remainder

I'm not really great at explaining stuff, but I hope this helps!

4 0

2 years ago

Find the area of the shaded region .

Greeley [361]

Calculate area of the white region inside circle.

Area of the two white triangles in top left and bottom right:

$2 \cdot \frac{1}{2}(6)(6) = 36 ft^2$

Area of the two white quarter circles in the bottom left and top right:

$2 \cdot \frac{1}{4}\pi (6)^2 = 18\pi ft^2$

Total area of unshaded white region inside circle:

$(36 + 18\pi)ft^2$

Area of entire circle including the white and shaded regions

$\pi(6)^2 = 36\pi ft^2$

Area of shaded region is area of entire circle - area of unshaded white region

$36\pi - (36 + 18\pi) = (18\pi - 36) ft^2$

7 0

3 years ago

Help meeeeeeeee answer these questions or correct them your like my human checker because calculators to check get boring

IRISSAK [1]

4 is 16.3, I don't know 5 or 6, 7 is 176, I don't know 8 or 9, 10 is 8.1, I don't know 11, and 12 is 48.
(I used a calculator, lol)

4 0

3 years ago