Answer:
I believe it's B!
Step-by-step explanation:
y=mx+b
y intercept is b
slope is m
y intercept is positive 5
slope is down 2 to the right 3
y= -2/3x+5
Answer:
k = -2
Step-by-step explanation:
2 way to solve:
1st: 8x²-13x-4k = 8(x²-(13/8)x-(k/2))
if 2 roots: a and 1/a
8(x-a)(x-1/a) = 8(x²-(13/8)x-(k/2))
x²-(a+1/a)x+1 = x²-(13/8)x-(k/2)
1 = -(k/2)
<u>k = -2</u>
<u>2nd:</u> 2 roots of 8x²-13x-4k x=(-b±√b²-4ac)/2a
x = (13±√169-4*8*(-4k))/16 = (13±√169+128k)/16
(13+(√169+128k))/16 = 16/ (13-(√169+128k)) ... root1=1/root2
(13+(√169+128k))*(13-(√169+128k)) = 16*16
13² - (√169+128k)² = 256
169-169-128k = 256
-128k = 256
k = -2
Answer:
-29/31
Step-by-step explanation:
We are given;
The equations;
2x+3y–5=0 and 5x=7y+3
We are required to determine the tangent of the angle between the two lines;
We need to know that;
When an equation is written in the form of, y = mx + c
Then, tan θ = m , where θ is the angle between the line and the x-axis.
Therefore, we can find the tangent of the angle between each line given and the x-axis.
2x+3y–5=0
we first write it in the form, y = mx + c
We get, y = -2/3x + 5/3
Thus, tan θ₁ = -2/3
5x=7y+3
In the form of y = mx + c
We get; y = 5/7x - 3/7
Thus, tan θ₂ = 5/7
Using the formula, θ = tan^-1((m1-m2)/(1+m1m2)) , where θ is angle between the two lines.
Thus, the tangent of the angle between the two lines will be;
tan θ = ((m1-m2)/(1+m1m2))
= ((-2/3-5/7)/(1 + (-2/3 × 5/7)))
= -29/21 ÷ 31/21
= -29/31
Thus, the tangent of the angle between the two lines is -29/31
Answer: sorry i don’t know i need to ask a question
explanation:
Answer:
14,18,20
Step-by-step explanation:
Substitute the s in the equation with the value given in the chart for s. So it would be 4 + 12 = 16.
