Question

Find the area of the given triangle. Round the answer to the nearest tenth.

Answer 1

Answer:

B) Area of triangle =  149.4 square units.

Step-by-step explanation:

Given : A triangle with sides 16 , 19, 27 .

To find : Area of a triangle.

Solution : We have given that triangle with sides 16 , 19, 27 .

Using heron's formula :

Area of triangle:  $\sqrt{s(s-a)(s-b)(s-c)}$.

Where, s = $\frac{a+b+c}{2}$ and a,b,c are sides of triangle.

Then s = $\frac{16+19+27}{2}$.

s = 31 units.

Area of triangle =  $\sqrt{31(31-16)(31-19)(31-27)}$.

Area of triangle =  $\sqrt{31(15)(12)(4)}$.

Area of triangle =  $\sqrt{22320)}$.

Area of triangle =  149.39 square units.

Area of triangle =  149.4 square units. ( nearest tenth)

Therefore, B) Area of triangle =  149.4 square units.

Answer 2

Using Heron's formula:
A = √(p(p-a)(p-b)(p-c)) where a,b,c are the sides of the triangle and p is half the perimeter.
The answer is B. 149.4 square units.