Question

Arrange the functions in ascending order, starting with the function that eventually has th least value and ending with the function that eventually has the greatest value.
3x+8
4^x+3
X^2+6
3x
4^x
X^2

Answer 1

Answer:

$3x,3x+8,x^{2} ,x^{2}+6,4^{x} ,4^{x}+3,$

Step-by-step explanation:

We have to arrange the functions given in ascending order which have eventually the least value and eventually the greatest value.

So, we get the following table representing the values of the functions for different values of x.

x                    :     5                   10                   15

$y_{1} =3x+8$    :     23               38                    53

$y_{2} =4^{x} +3$   :    1027         1048579          1073741827

$y_{3} =x^{2} +6$   :     31                106                   231

$y_{4} =3x$        :     15                30                     45

$y_{5} =4^{x}$        :     1024       1048576        1073741824

$y_{6} =x^{2}$        :      25              100                    225

As, can be seen from the table that the ascending order of the functions is given by $y_{4},y_{1},y_{6},y_{3},y_{5},y_{2},$.

Hence, the order is $3x,3x+8,x^{2} ,x^{2}+6,4^{x} ,4^{x}+3,$.