For number one the second card must be positive or he would have to put it back if its negative for number 2 the card must be 3 4 5 because negative 2 plus 3 is 1 which is positive and negative 2 plus 4 and 5 would allow her to keep her cards. for the third one danny could have pulled a negaitive 1 2 3 4 and 5. oh dude i forgot to put decimals but still the same thing
Question 9.)
5-2(5)-1
10-1
Y=9
(X,Y) = 5,9
2- 2(2)-1
4-1
Y=3
(X,Y)= 2,3
0- 2(0)-1
2-1
Y=1
(X,Y)= 0,1
10)
4- 3(4)-7
12-7
Y=5
(X,Y)=4,3
1- 3(1)-7
3-7
Y=-4
(X,Y)= 1,-4
0- 3(0)-7
0-7
Y=-7
(X,Y)= 0,-7
(I believe you are supposed to plot the (X,Y) points on the graph)
Answer:
P ( 1.2 < X < 2.1 ) = 0.3
Step-by-step explanation:
Given:
Uniform distribution over interval (0,3) can be modeled by a probability density function f(x)
f(x) = 1 / (b - a)
Where a < x < b is the domain at which function is defined:
f(x) = 1 / (3) = 1 / 3
Where, X - U ( u , δ )
u = ( a + b ) / 2 = (0 +3) / 2 = 1.5
δ = ( b - a ) / sqrt (12) = (3 - 0) / sqrt (12) = 0.866
Hence,
X - U ( 1.5 , 0.866 )
There-fore calculating P ( 1.2 < X < 2.1 ):
Where, a = 1.2 and b = 2.1
P ( 1.2 < X < 2.1 ) = x / 3 |
P ( 1.2 < X < 2.1 ) = 2.1 /3 - 1.2 / 3 = 0.3
Answer: P ( 1.2 < X < 2.1 ) = 0.3
13.
1st: split the 1 shape into 2 shapes. (spit across to where you see one right angle(top), and a trapezoid(bottom)
2nd: now what i did was fill that gap to where the total height is 9 and the total length is 7. ( if you don't want to do that it is fine )
3rd: for the top do 5 times 2 = 10
4th: for the bottom do 4 times 5 = 20
5th: add 10 (top) and 20 (bottom) = 30
64 players
Reason- 2/3 of 96 = (32 x 2 = 64) telling us how many got on the list
