What is the least integer value in the solution set to 7(3x – 1) ≤ 4x? –1 2 3 7

Mathematics

1 answer:

Ahat [919]3 years ago

3 0

Answer:

the answer is 3

Step-by-step explanation: just took the quiz on edge

You might be interested in

Factoring a quadratic with leading coefficient greater than 1 <br><br><br> 2y^2+17y-9

abruzzese [7]

Multiply first and last coefficients:
2*(-9) = -18

Find 2 factors which multiply to -18 and add up to 17:
18 and -1

Rewrite quadratic with 17y split up as' 18y - y', Then factor by grouping:

$2y^2 - y + 18y -9 \\ \\ y(2y-1) + 9(2y-1) \\ \\ (2y-1)(y+9)$

4 0

3 years ago

If z1 = 12(cos55° + isin55°) and z2 = 4(cos95° + isin95°), then |z1z2|= ???

zaharov [31]

$\bf \begin{cases}
z_1=12[cos(55^o)+i~sin(55^o)]\\\\
z_2=4[cos(95^o)+i~sin(95^o)]
\end{cases}\\\\
-------------------------------$

$\bf ~~~~~~\textit{ product of two complex numbers}\\\\
{{ r_1}}[cos({{ \alpha}})+isin({{ \alpha}})]\quad \cdot \quad {{ r_2}}[cos({{ \beta}})+isin({{ \beta}})]
\\\\\\
\implies {{ r_1\cdot r_2}}[cos({{ \alpha}} + {{ \beta}})+isin({{ \alpha}} + {{ \beta}})]\\\\
-------------------------------\\\\
z_1\cdot z_2\implies 12\cdot 4[cos(55^o+95^o)+i~sin(55^o+95^o)]
\\\\\\
48[cos(150^o)+i~sin(150^o)]
\\\\\\
|~48[cos(150^o)+i~sin(150^o)]~|\implies 48[cos(150^o)+i~sin(150^o)]$

6 0

3 years ago

What are different solutions of 1x +2y = 12

miv72 [106K]

Answer:

x=12, y=6

Step-by-step explanation:

Very simple!

Just substitute 0 for y and solve for x!

$x+2(0)=12$ (anything times 0 equals 0!)