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3 years ago

Could someone tell me how to do the first one and how to do the second one pleaese

Mathematics

1 answer:

Yuri [45]3 years ago

7 0

1 is A
2 is coming think

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how can you copy a line segment using a straightedge, a compass, and a pencil, give step by step instructions

GuDViN [60]

You can can copy a line segment by making sure the line is straight

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2 years ago

Which is the most likely meaning of the word anachronous? (1 point)

ad-work [718]

Answer:

Not in the right time

Step-by-step explanation:

ana is the root of before and chronous=krounus, being the Greek word for time.

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2 years ago

In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.

ankoles [38]

<h2>Answer:</h2>

$\boxed{\overline{MN}=37.96}$

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find $\overline{MN}$ . Since:

$\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm$

and $\overline{MN}$ is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

$\overline{RN}=\overline{QN}$

By Pythagorean theorem, for triangle NQP:

$\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}$

Applying Pythagorean theorem again, but for triangle MQN:

$\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}$

3 0

3 years ago

Sybil has 1/2 of pizza left over. She wants to share the pizza with 3 of her friends. What fraction of the original pizza does s

Vadim26 [7]

Answer:

1/6

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Which shows the terms of the series? 4 12 48 192 4 12 36 3 12 48 192 3 12 48

Stells [14]

The value of the term in the series will be equal to 3 + 12 +48 + 192 after calculation.

<h3>What is summation?</h3>

In mathematics, the summation is the addition of a sequence of any kind of numbers, called addends or summands.

Now we have a given term

$\sum_{n=1}^{4} 3(4)^{n-1}$

By solving the above term;

$\sum_{n=1}^{4} 3(4)^{n-1}=3(4)^{1-1}+3(4)^{2-1}+3(4)^{3-1}+3(4)^{4-1}$

$\sum_{n=1}^{4} 3(4)^{n-1}=3(4)^0+3(4)^1+3(4)^2+3(4)^3$

$\sum_{n=1}^{4} 3(4)^{n-1}=3 + 12 +48 + 192$

Hence the value of the term in the series will be equal to 3 + 12 +48 + 192 after calculation.

To know more about Summation follow

brainly.com/question/2767605

5 0

2 years ago