We have been given image of circle that passes through point . We are asked to find the radius of the circle.
First of all, we will find the center of the circle.
We can see that center of circle is at point .
Now we will use equation of circle to find radius.
, where, point (h,k) represents center of circle and r represents radius of circle.
Now we will substitute the coordinates of point and coordinates of center and solve for r as:
Switch sides:
Now we will take positive square root on both sides:
Therefore, radius of circle will be and center is at point .
If you meant to write (x-2)^2 + (y-6)^2 = 4, then the center is (2,6). The statement would be true.
This is because the general form (x-h)^2 + (y-k)^2 = r^2 describes a circle centered at (h,k) with radius r. In this case, h = 2, k = 6, r = 2. Note how r^2 = 4 so r^2 = 2^2 leads to r = 2.
Answer:
they all cancel out it would be 0
Step-by-step explanation:
X + 36 = 16
16 - 36 = -20
X = -20
Step-by-step explanation:
(3,2) is the solution to both equations because if you substitute the the x and y values you get a true statement for example
6(3) + 7(2) =32
18 + 14 = 32
32=32
that is a true statement
you can do the same with system B
8(3) +8(2)=40
24 + 16 = 40
40 =40
which is a true statement