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kozerog [31]
2 years ago
5

Scott drove 871 miles in 13 hours. At the same rate, how long would it take him to drive 469 miles?

Mathematics
1 answer:
olga55 [171]2 years ago
4 0

871 miles ........... 13 hours

469 miles ............x hours

x = 469×13/871 = 7 hours

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
(1+5i) + (-8+i) ? <br> Need answer and steps
Shtirlitz [24]

Answer:

6\sqrt{-1}-7

Step-by-step explanation:

simplyifying this we get

1+5i-8+i

= 6i-7

I am assuming the i you are talking about here is the sqrt of negative one so that would be 6\sqrt{-1}-7

7 0
3 years ago
What is the range of this function?
Rzqust [24]

Greetings.

The range is the set of y-value.

The range starts from the minimum point to maximum point.

Our minimum point starts at 0 and maximum point starts less than infinity.

Therefore the range is 0<=y<+inf

However, we do not often write that, although it is right.

Therefore we write as y≥0

Thus, the answer is B choice.

5 0
2 years ago
Each of the four sets a1, a2, a3, and a4 contains four elements. the intersection of every i of these four sets (2 &lt; i &lt; 4
hammer [34]

Answer:

trick question. the man is gay

Step-by-step explanation:

5 0
3 years ago
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Y=7x-3. y=-7x+3<br><br> What type of solution is this?
aivan3 [116]
One solution: (3/7, 0)
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3 years ago
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