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<h3>f(x) = -3·2^(x-1) -1</h3>
- reflection across the x-axis (multiplication by -1)
- vertical expansion by a factor of 3 (multiplication by 3)
- shift to the right 1 unit (replace x with x-1)
- shift down 1 unit (add -1 to the function value)
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<h3>f(x) = -1/4·2^(x+1) -1</h3>You may notice this is the same as the previous question, but with the vertical expansion factor 1/4 instead of 3, and the horizontal shift left instead of right.
- reflection across the x-axis (multiplication by -1)
- vertical compression by a factor of 4 (multiplication by 1/4)
- shift to the left 1 unit (replace x with x+1)
- shift down 1 unit (add -1 to the function value)
Answer:
2x+59.
Step-by-step explanation:
Let <em>J </em>represent Jessica's weight and <em>R</em> represent Ronda's weight.
Jessica weighs <em>x+34</em> pounds. Thus:
Ronda weighs 12 pounds less than Jessica. In other words:
The sum of their weights, therefore, is:
Now, if Jessica gains 5 pounds and Ronda loses 2 pounds, the net gain of the total weight would be 3 pounds. Thus, we only need to add 3 to the original total to find the sum of their new weights:
The sum of the new [weights] is represented by 2x+59.