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xxMikexx [17]
3 years ago
14

Help plz...............

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0
Y = -4(x - 2)² + 4
This equation is in vertex form. 

y = a(x - h)² + k
(h,k) is the vertex.

(h, k) = (2, 4)
axis of symmetry x = 2

So it will be the graph with a point at (2, 4).
Also remember that it opens downward because the a is negative.

The graph is the upper right one.
vertex is (2, 4).
x = 2

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The area of a square quilt is 196 square inches. There is a smaller square patch on the quilt with an area of 49 square inches.
Makovka662 [10]




To find your answer you would find the perimeter of the small square which is 28.

You would then find the perimeter of the big square which is 56. 

Next, you subtract 56 from 28 and get 28.  

So the difference is 28 inches.

Hope this helps!!



5 0
3 years ago
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Please help me 5-7g-3=
Archy [21]

Answer: −7g+2

If I Helped, Please Mark Me As Brainliest, Have A Great Day :D

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What are the points for f(x)=3^(x-1)-2
Savatey [412]

Answer:  (0, -1 \frac{2}{3}), (1, -1), (2, 1)

<u>Step-by-step explanation:</u>

Set the exponent equal to zero - <em>that is your anchor point</em>.

Then choose an x-value less than and greater than the anchor point.

\left\begin{array}{c|c|l}&\underline{\quad x\quad }&\underline{\qquad \qquad f(x)\qquad \qquad \qquad \quad }\\\text{less than anchor}&0&3^{0-1}-2=3^{-1}-2=\frac{1}{3}-2 = -1\frac{2}{3}}\\\\anchor\ point&1&3^{1-1}-2=3^{0}-2=1-2 = -1}\\\\\text{greater than anchor}&2&3^{2-1}-2=3^{1}-2=3-2 = 1}\end{array}\right

4 0
4 years ago
Which country was the first to industrialize on the continent of Europe
maxonik [38]

britain is your answer

5 0
3 years ago
Write 9x² - 36x = 4y² + 24y + 36 in standard form
Kisachek [45]

Answer:

9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;

(x - 2)²/2² - (y + 3)²/3² = 1

Step-by-step explanation:

The standard form of a hyperbola is given as follows;

(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1

The given equation is presented as follows;

9·x² - 36·x = 4·y² + 24·y + 36

By completing the square, we get;

(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)

(3·x - 6)² - 36 = (2·y + 6)²

(3·x - 6)² - (2·y + 6)² = 36

(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1

(3·x - 6)²/6² - (2·y + 6)²/6² = 1

3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1

(x - 2)²/2² - (y + 3)²/3² = 1

The equation of the hyperbola  is (x - 2)²/2² - (y + 3)²/3² = 1.

5 0
3 years ago
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