Simplify 3 upon 10 + 4 upon 5 3^10 + 4^5
1 answer:
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As you can see in the given figure, there are two intersecting chords inside the circle.
Recall that the "Intersecting Chords Theorem" is given by
For the given case, we have
AE = 7
BE = 6
EC = 9
Let us substitute these values into the above equation and solve for DE
Therefore, the length of DE is 10.5 units.
We'll use the Law of Cosines
We'll call
side a = length 5
side b = length 8
side c = length 10
and their corresponding angles as A, B and C
"C" would be the largest angle
cos (C) = (a^2 + b^2 - c^2) / 2 * a * b
cos (C) = (5^2 + 8^2 - 10^2) / 2 * 5 * 8
cos (C) = 25 + 64 -100 / 80
cos (C) = -11 / 80
cos (C) = <span> <span> <span> -0.1375 </span> </span> </span>
arc cosine ( <span> <span> <span> -0.1375 </span> </span> </span> ) = 97.903 Degrees
The largest angle is 97.903 Degrees
We'll call
side a = length 5
side b = length 8
side c = length 10
and their corresponding angles as A, B and C
"C" would be the largest angle
cos (C) = (a^2 + b^2 - c^2) / 2 * a * b
cos (C) = (5^2 + 8^2 - 10^2) / 2 * 5 * 8
cos (C) = 25 + 64 -100 / 80
cos (C) = -11 / 80
cos (C) = <span> <span> <span> -0.1375 </span> </span> </span>
arc cosine ( <span> <span> <span> -0.1375 </span> </span> </span> ) = 97.903 Degrees
The largest angle is 97.903 Degrees
Answer:
The height of the light pole to the nearest foot is approximately 50 feet
Step-by-step explanation:
The parameters given in the question are;
The length of the cable = 63 feet
The angle of elevation of the cable to the top of the light pole = 52°
With the assumption that the light pole is perpendicular to the ground, the figure formed by the light pole, the distance of the of the cable from the base of the light pole and the length of the cable form a right triangle
The question can be answered by using trigonometric relations for the sine of the given angle as follows;
The opposite leg length of the formed right triangle = The height of the light pole
The hypotenuse length = The length of the cable = 63 feet
The angle, θ = The angle of elevation = 52°
Plugging in the values, gives;
∴ The height of the light pole = 63 feet × sin(52°) ≈ 49.645 feet
The height of the light pole to the nearest foot ≈ 50 feet.