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ipn [44]
3 years ago
7

How does the range of g(x)=6/x compare with the range of the parent function (f)=1/x?

Mathematics
1 answer:
kogti [31]3 years ago
7 0
Since the only exclusion from the range is y=0, vertically scaling the graph by a factor of 6 doesn't change the range. (0 is still 0)

The appropriate choice is ...
   <span>B: The range of both f(x) and g(x) is all nonzero real numbers</span>
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Answer:

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Step-by-step explanation:

Here it's given that ,

\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}

Also ,

\sf\red{\longrightarrow} s =\dfrac{a+b+c}{2}

And we need to find out the value of A , when

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So , on substituting the respective values to find s we have ,

\sf\red{\longrightarrow} s =\dfrac{3+4+5}{2}=\dfrac{12}{2}=\bf{6}

Now let's find out A as ,

\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)} \\

\sf\red{\longrightarrow}A =\sqrt{6 * 3 * 2 * 1}\\

\sf\red{\longrightarrow} A = \sqrt{3^2 * 2^2 *1^2}\\

\sf\red{\longrightarrow}A = 3*2\\

\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}

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Step-by-step explanat ion :

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