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Nina [5.8K]
3 years ago
9

A lab technician has to fill the tank given below. Find it’s volume .

Mathematics
1 answer:
wel3 years ago
6 0

Answer:

The volume of the cylinder shown in the figure is 628 cube meters

Step-by-step explanation:

Given figure is about cylinder

The height of the cylinder = h = 8 meters

The radius of the base of cylinder = r = 5 meters

Now, let The volume of cylinder = V m³

So, The volume of cylinder is given as V = \pi×r²×h

where r is the radius of its base

And h is the height of cylinder

The value of  \pi = 3.14

So, V =  \pi × r² × h

Or, V = 3.14 × (5)² × 8

Or, V =  3.14 × 25 × 8

or, V = 628 m³

So, The volume of cylinder = V  = 628 m³

Hence The volume of the cylinder shown in the figure is 628 cube meters  Answer

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The cost of item A is $8 and the
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Answer: the number of item A that you sold is 11

the number of item B that you sold is 2

Step-by-step explanation:

Let x represent the number of item A that you sold.

Let y represent the number of item B that you sold.

The total number of item A and item B sold is 13. This means that

x + y = 13

The cost of item A is $8 and the

cost of item B is $4. The total amount if money made is $88. This means that

8x + 4y = 88 - - - - - - - - - -1

Substituting x = 13 - y into equation 1, it becomes

8(13 - y) + 4y = 88

104 - 8y = 88

8y = 104 - 88 = 16

y = 16/8 = 2

x = 13 - y = 13 - 2 = 11

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Two major automobile manufacturers have produced compact cars with engines of the same size. We are interested in determining wh
Molodets [167]

Answer:

(A) The mean for the differences is 2.0.

(B) The test statistic is 1.617.

(C) At 90% confidence the null hypothesis should not be rejected.

Step-by-step explanation:

We are given that a random sample of eight cars from each manufacturer is selected, and eight drivers are selected to drive each automobile for a specified distance.

The following data (in miles per gallon) show the results of the test;

Driver         Manufacturer A               Manufacturer B

   1                      32                                       28

  2                      27                                       22

  3                      26                                       27

  4                      26                                       24

  5                      25                                       24

  6                      29                                       25

  7                       31                                       28

  8                      25                                       27

Let \mu_1 = mean MPG for the fuel efficiency of Manufacturer A brand

\mu_2 = mean MPG for the fuel efficiency of Manufacturer B brand

SO, Null Hypothesis, H_0 : \mu_1-\mu_2=0  or  \mu_1= \mu_2    {means that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles}

Alternate Hypothesis, H_A : \mu_1-\mu_2\neq 0  or  \mu_1\neq  \mu_2   {means that there is a significant difference in the mean MPG (miles per gallon) for the fuel efficiency of these two brands of automobiles}

The test statistics that will be used here is <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                      T.S.  = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t__n__1+_n__2-2

where, \bar X_1 = sample mean MPG for manufacturer A = \frac{\sum X_A}{n_A} = 27.625

\bar X_2 = sample mean MPG for manufacturer B =\frac{\sum X_B}{n_B} = 25.625

s_1 = sample standard deviation for manufacturer A = \sqrt{\frac{\sum (X_A-\bar X_A)^{2} }{n_A-1} } = 2.72

s_2 = sample standard deviation manufacturer B = \sqrt{\frac{\sum (X_B-\bar X_B)^{2} }{n_B-1} } = 2.20

n_1 = sample of cars selected from manufacturer A = 8

n_2 = sample of cars selected from manufacturer B = 8

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} }   =  \sqrt{\frac{(8-1)\times 2.72^{2}+(8-1)\times 2.20^{2}  }{8+8-2} }  = 2.474

(A) The mean for the differences is = 27.625 - 25.625 = 2

(B) <u><em>The test statistics</em></u>  =  \frac{(27.625-25.625)-(0)}{2.474 \times \sqrt{\frac{1}{8}+\frac{1}{8}  } }  ~  t_1_4

                                     =  1.617

(C) Now at 10% significance level, the t table gives critical values between -1.761 and 1.761 at 14 degree of freedom for two-tailed test. Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles.

5 0
4 years ago
What makes n true 1/2 (n+4)=6
AlexFokin [52]

Answer: N=8

Step-by-step explanation: So 1/2*4=2 then you know that you need 4 to get to six because you already have two. Then 8/2=4 so N=8.

1/2(8+4)=6

4+2=6

6=6

Hope this helped!!!!!

8 0
3 years ago
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