Remark
Sometimes you can avoid the distributive property. This is one of those cases. Start by dividing by 5. You can only do this is there a common factor between the left and right sides of the equal sign.
Solve
There is only 1 solution. If there was an x^2 somewhere, you would have 2 and if there was an x^3 there would be 3.
5(2x - 3) = 5 Divide both sides by 5
5(2x - 3)/5 = 5/5
(2x - 3) = 1 Remove the brackets.
2x - 3 = 1 Add 3 to both sides.
2x = 1 + 3
2x = 4 Divide by 2
x = 4/2
x = 2 <<<<< Answer
Answer:
24cm squared
Step-by-step explanation:
do base x height = 48 then as it is half of a square you half it.
Answer: (94.08, 101.92)
Step-by-step explanation:
The confidence interval for unknown population mean
is given by :-
![\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%5Cpm%20z%5E%2A%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
, where
= Sample mean
= Population standard deviation
z* = Critical z-value.
Given : A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12.
![\sigma= 12](https://tex.z-dn.net/?f=%5Csigma%3D%2012)
![\overline{x}=98](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%3D98)
n= 36
Confidence interval = 95%
We know that the critical value for 95% Confidence interval : z*=1.96
Then, the 95% confidence interval for the mean of x will be :-
![98\pm (1.96)\dfrac{12}{\sqrt{36}}](https://tex.z-dn.net/?f=98%5Cpm%20%281.96%29%5Cdfrac%7B12%7D%7B%5Csqrt%7B36%7D%7D)
![=98\pm (1.96)\dfrac{12}{6}](https://tex.z-dn.net/?f=%3D98%5Cpm%20%281.96%29%5Cdfrac%7B12%7D%7B6%7D)
![=98\pm (1.96)(2)](https://tex.z-dn.net/?f=%3D98%5Cpm%20%281.96%29%282%29)
![=98\pm 3.92=(98-3.92,\ 98+3.92)\\\\=( 94.08,\ 101.92)](https://tex.z-dn.net/?f=%3D98%5Cpm%203.92%3D%2898-3.92%2C%5C%2098%2B3.92%29%5C%5C%5C%5C%3D%28%0994.08%2C%5C%20101.92%29)
Hence, the 95% confidence interval for the mean of x is (94.08, 101.92) .
Answer:
WhAt where is the rest if this is it than wow
Step-by-step explanation: