Hello,
Let's assume f the age of the father,
s the age of the son.
<span>The age of a father is 2 less than 7 times the age of his son ==> f=7s-2 (1)
</span>
<span>In 3 years, the sum of their ages will be 52 ==>(f+3)+(s+3)=52 (2)
(2)==>f+s+6=52
==>f+s=46 (3)
(3) and (1) ==>7s-2+s=46
==>8s=48
==>s=6
f=46-6=40
</span>
Answer:
7^4
Step-by-step explanation:
7 to the power of 4
Answer:
the answer for that would be 2n^2-7
First is to add the ratios 3:4
3+4=7
3/7= 0.43
4/7= 0.57
56 x 0.43 = 24
56 x 0.57 = 32
Therefore 3:4 is 24:32 which is 56.
